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natta225 [31]
2 years ago
5

Submit Test

Mathematics
1 answer:
andrey2020 [161]2 years ago
6 0
Cut out the diagram so your answer is B
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Hmm that’s tuff I have no idea
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1 year ago
6=2(y+2) i need help
Snowcat [4.5K]

Answer:

y=1

Step-by-step explanation:

6=2(y+2)

6=2y+4

2=2y

y=1

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Jackson is buying a new TV for $650. He will also be
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Answer:

his total bill would be 698.75

Step-by-step explanation

you only did half of the problem lol.

48.75 is just the sales tax. to get the total bill, you need to add 650 to 48.75 because 650 is the actual price of the TV

hope this helps :)

8 0
3 years ago
Read 2 more answers
For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

8 0
2 years ago
Jon is allowed to play video games 5 hours throughout the week. so far this week , he has spent 2 5/6 hours playing games . how
Ivahew [28]
B: 2 and 1/6.

Tricky one if you rush through, its meant to SEEM complicated, like a lot of math questions.
8 0
3 years ago
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