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notsponge [240]
3 years ago
10

Please help i dont understand!!!

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0
The answer is
\\  {a}^{  - \frac{ 13}{5} }  \\ or \\ a {}^{ - 2.6}


good luck
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Please help! really needing help solve the problem
guapka [62]

Answer:

7

Step-by-step explanation:

By Basic proportionality theorem:

\frac{10}{8}  =  \frac{3x - 6}{12}  \\  \\  \frac{10 \times 12}{8}  = 3x - 6 \\  \\  \frac{120}{8}  = 3x - 6 \\  \\ 15 = 3x - 6 \\ 15 + 6 = 3x \\ 21 = 3x \\  \frac{21}{3}  = x \\ 7 = x \\  \\  \huge \red { \boxed{x = 7}}

7 0
3 years ago
Find the price per bottler of water if 12 bottles of water cost $4.49
sweet-ann [11.9K]
About $0.37 because you divide $4.49 by 12
5 0
3 years ago
The area of a baseball field bounded by home plate, first base, second base, and third base is a square. If a player at first ba
slega [8]

Answer:

120ft

Step-by-step explanation:

If the bases are 120ft apart from each other you would have to find the distance of going from first to second then to third. Then you divide it in half because you arent going around the diamond, you are cutting right through it.

8 0
2 years ago
Read 2 more answers
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
64/9 to a mixed number
Verizon [17]
\dfrac{64}{9}=7\dfrac{1}{9}
5 0
3 years ago
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