I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Answer:
bigger angle is 66° ......
I believe the answer 59.5 sorry if wrong
If cos θ = (-5/13), then θ should be in quadrant II or III. The given says sin θ < 0, so θ should be in quadrant III. In this case, tan <span>θ should be equal to number greater than zero. Hence we get sqrt of (13^2 - 5^2 ) equal to 12. tan </span><span> θ should be equal to A 12/5. </span>
25000=X [((1-(1+0.078)^(-5))/0.078]
Solve for x
X=6228.44