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Ede4ka [16]
2 years ago
7

1) Which shows 5/90 in decimal form?

Mathematics
2 answers:
docker41 [41]2 years ago
7 0
1) answer is <span>D 0.0555...
2 answer is </span><span>B -0.535</span>
prohojiy [21]2 years ago
4 0
D, and if you have a repeating decimal, just put a line over the 2 numbers after the decimal. B, because on the calculator can't put a negitive sign, so I would use a online calculator for negitives. Hoped this helped you!
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Which of the following equations matches the function shown above?
yanalaym [24]

Answer:

C=y=sin1/2x

Step-by-step explanation:

As given in the graph:

Amplitude= 1

period=2π

Finding function of sin that have period of 4π and amplitude 1

A: y=1/2sinx

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1/2

b=1

c=0

d=0

Amplitude=|a|

                =1/2

Period= 2π/b

         =2π

B: y=sin2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/2

         =π

C: y=sin1/2x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/2

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/2

         =4π

D: y=sin1/4x

Using the formula  asin(bx-c)+d to find the amplitude and period

a=1

b=1/4

c=0

d=0

Amplitude=|a|

                =1

Period= 2π/1/4

         =8π

Hence only c: y=sin1/2x has period of 2π and amplitude 1

5 0
3 years ago
I need help please either discord me the answer at F4deG0d#0988 or do it on here cause this is important.
algol13

Answer:

x= 12.5

So

2x = 25

4x = 50

6x = 75

Step-by-step explanation:

line CG is 180 degrees, so 12x + 30 = 180

x = 12.5

7 0
3 years ago
In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?
Sophie [7]

Answer: 1440

Step-by-step explanation:

To arrange 3 boys and 4 girls such that no two boys are together.

Since boys should be arranged between the girls.

So first arrange the girls.

Assume that the girls are placed, then there will be 5 spaces left for 3 boys.

The number of combinations to fill these places = ^5C_3=\dfrac{5!}{3!2!}=\dfrac{5\times4}{2}=10

Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways

4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways

Then, the total number of arrangements = 10 x 6 x 24 = 1440

Hence, the required number of arrangements = 1440

5 0
2 years ago
How many radians is 105°?
Katen [24]

Answer:

The answer is 1.833 radians

7 0
3 years ago
Read 2 more answers
Find the values of x, y, and z.<br> X=?<br> Y=?<br> Z=?
astraxan [27]
I haven’t taken geometry in a couple years, so I hope this is right. I’m so sorry if it’s not!!

X= 91

Y= 62

Z= 45
4 0
2 years ago
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