Answer:
The probability that the child will have type blood B equals <u>3/16</u>.
Explanation:
<u>Available data:</u>
- Individuals with the rare Bombay blood phenotype lack both the A and B antigens in individuals and/or are of hh genotype.
- Cross between two parents that are both of I A I B Hh genotype
Cross: IAIB Hh x IAIB Hh
Gametes) IAH, IAh, IBH, IBh
IAH, IAh, IBH, IBh
Punnett square) IAH IAh IBH IBh
IAH IAIAHH IAIAHh IAIBHH IAIBHh
IAh IAIAHh IAIAhh IAIBHh IAIBhh
IBH IAIBHH IAIBHh IBIBHH IBIBHh
IBh IAIBHh IAIBhh IBIBHh IBIBhh
F1) Genotype
- 1/16 IAIA HH
- 2/16 IAIAHh
- 1/16 IAIAhh
- 2/16 IAIBHH
- 4/16 IAIBHh
- 2/16 IAIBhh
- 1/16 IBIBHH
- 2/16 IBIBHh
- 1/16 IBIBhh
Phenotype
- 3/16 Blood type A
- 6/16 Blood type AB
- 3/16 Blood type B
- 3/16 Blood type 0
I filled out a few boxes for you to start you off. I also gave you a direct research sources for some animals that will take you to the necessary information.
This is what I have so far as examples for you. Again, I said I wouldn't do all of your work for you, however, I will help you through your research and graph.
Answer: Option C.
C)the tails of plant lipids cannot pack as tightly together as animal ones
Explanation:
The tails of plant lipids cannot pack as tightly together as animal ones because the double bond in plant lipids make the hydrocarbon chains to bend making them no to pack tightly together which cause a reduction in van der Waals interaction between the fatty acids. The length of the double bond also affect the melting point of fatty acids . If the hydrocarbon chain is long, melting point will be high .
D. Growth, Metabolism, and Differentiation.
