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frozen [14]
3 years ago
14

a family has two cars. the first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of

15 miles per gallon of gas. during one particular week, the two cars went a combined total of 850 miles, for a total gas consumption of 50 gallons. how many gallons were consumed by each of the two cars that week?
Mathematics
1 answer:
Kryger [21]3 years ago
3 0
Let the number of gallons consumed be the first car be x, and that of the second car, y. Then:
x + y = 50 . . . . . . . (1)
20x + 15y = 850. . . (2)

(1) x 20 => 20x + 20y = 1000 . . . (3)
(2) - (3) => -5y = -150 => y = -150/-5 = 30

From (1), x + 30 = 50 => x = 50 - 30 = 20

Therefore, first car consumed 20 gallons and the second consumed 30 gallons.
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pav-90 [236]
Well I don't know ! 
Let's take a look and see:

The idea is that there could be more than one way
for a roll of the dice to land with the same number.  

-- If the sum is from 1-4, you get the point.
There are  6  different ways for a roll of the dice to come up 1-4.

-- If the sum is from 5-8, Adam gets the point.
There are  20  different ways for a roll of the dice to come up 5-8.

-- If the sum is 9-12, Lana gets the point.
There are  10  different ways for a roll of the dice to come up 9-12.

-- The game is not fair to all three of you.
-- Lana has a distinct advantage over you.
-- Adam has a big advantage over Lana.
-- Adam has an even bigger advantage over you.
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_______________________________

Here's how to figure it:

Ways to roll a 2:
1 ... 1

Ways to roll a 3:
1 ... 2
2 ... 1

Ways to roll a 4:
1 ... 3
2 ... 2
3 ... 1

Ways to roll a 5:
1 ... 4
2 ... 3
3 ... 2
4 ... 1

Ways to roll a 6:
1 ... 5
2 ... 4
3 ... 3
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Ways to roll a 7:
1 ... 6
2 ... 5
3 ... 4
4 ... 3
5 ... 2
6 ... 1

Ways to roll an 8:
2 ... 6
3 ... 5
4 ... 4
5 ... 3
6 ... 2

Ways to roll a 9:
3 ... 6
4 ... 5
5 ... 4
6 ... 3

Ways to roll a 10:
4 ... 6
5 ... 5
6 ... 4

Ways to roll 11:
5 ... 6
6 ... 5

Ways to roll 12:
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