Question

How to solve 8(4-r)=-6(3+r)​

Answer 1

Answer:

$\boxed{\bold{r=25}}$

Step By Step Explanation:

Expand $\bold{8\left(4-r\right): \ 32-8r}$

Expand $\bold{-6\left(3+r\right): \ -18-6r}$

Rewrite Equation

$\bold{32-8r=-18-6r}$

Subtract 32 From Both Sides

$\bold{32-8r-32=-18-6r-32}$

Simplify

$\bold{-8r=-6r-50}$

Add 6r To Both Sides

$\bold{-8r+6r=-6r-50+6r}$

Simplify

$\bold{-2r=-50}$

Divide Both Sides By -2

$\bold{\frac{-2r}{-2}=\frac{-50}{-2}}$

Simplify

$\bold{r=25}$