This problem can be readily solved if we are familiar with the point-slope form of straight lines:
y-y0=m(x-x0) ...................................(1)
where
m=slope of line
(x0,y0) is a point through which the line passes.
We know that the line passes through A(3,-6), B(1,2)
All options have a slope of -4, so that should not be a problem. In fact, if we check the slope=(yb-ya)/(xb-xa), we do find that the slope m=-4.
So we can check which line passes through which point:
a. y+6=-4(x-3)
Rearrange to the form of equation (1) above,
y-(-6)=-4(x-3) means that line passes through A(3,-6) => ok
b. y-1=-4(x-2) means line passes through (2,1), which is neither A nor B
****** this equation is not the line passing through A & B *****
c. y=-4x+6 subtract 2 from both sides (to make the y-coordinate 2)
y-2 = -4x+4, rearrange
y-2 = -4(x-1)
which means that it passes through B(1,2), so ok
d. y-2=-4(x-1)
this is the same as the previous equation, so it passes through B(1,2),
this equation is ok.
Answer: the equation y-1=-4(x-2) does NOT pass through both A and B.
Answer:
yes
the domain is greater than or equal to 0 and less than or equal to 4
the range is greater than or equal to 2 and less than or equal to 4
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Center: (-3, 4)
radius = r = 
= 5
diameter = 2r = 10
Answer:
Q1: 7, 10, 13, 16 10th Term = 34
Q2: -1, 3, 7, 11 10th Term = 35
Q3: 11, 10, 9, 8 10th Term = 2
Q4: 3, 1, -1, -3 10th Term = -15
Step-by-step explanation:
I don't know If this is the answer you wanted but please tell me If I'm right or wrong.
