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blsea [12.9K]
3 years ago
8

Geometry help needed, thanks!!

Mathematics
1 answer:
Anon25 [30]3 years ago
8 0

Answer:

Part 1) 0.669

Part 2) x=23.78 cm

Step-by-step explanation:

Part 1) we have

cos(48°)

Using a calculator

cos(48°)=0.66913

Round to the nearest thousandth

0.66913=0.669

Part 2) we know that

In the right triangle of the figure

The cosine of angle of 18 degrees is equal to divide the adjacent side to the angle of 18 degrees by the hypotenuse of the right triangle

so

cos(18°)=x/25

x=(25)cos(18°)=23.78 cm

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\sqrt{ x^{2}-10x+25}+25+12\sqrt{x} =15\sqrt{x} \\  \\  \therefore \: \sqrt{ x^{2}-10x+ {5}^{2} }+25 =15\sqrt{x} - 12\sqrt{x}\\  \\  \therefore \: \sqrt{( x - 5)^{2}}+25 =3\sqrt{x}  \\  \\ \therefore \:  x - 5+ 25 = 3 \sqrt{x}  \\  \\ \therefore \: x + 20 = 3 \sqrt{x}  \\  \\ squaring \: both \: sides \\ (x + 20)^{2}  = ( {3 \sqrt{x} })^{2}  \\ \therefore \:  {x}^{2}  + 40x + 400 = 9x \\ \therefore \:  {x}^{2}  + 40x + 400  - 9x = 0 \\  \therefore \:  {x}^{2}  + 31x + 400  = 0 \\

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