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VMariaS [17]
3 years ago
10

Kelly is making a triangular chicken coop as shown in the diagram below. She is going to fence in the area for her chickens.

Mathematics
1 answer:
amm18123 years ago
4 0

Answer: the answer is 48 feet

Step-by-step explanation: 24+ 12+ 12=48

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Justify Step 4 of this Proof
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I believe it's SSS

Step-by-step explanation:

This is because all sides are congruent to each other.

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A tree casts a shadow 27 m long. At the same time, the shadow cast by a 66-cm tall statue is 56 cm long. Find the height of the
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\frac{height _{1} }{shadow_{1}} =  \frac{height _{2} }{shadow_{2}}

\frac{height _{1} }{27m} = \frac{66cm}{56cm}

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178200=56h _{1}

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Bill is planning to paint the back of his house. What is the total area that he will be painting?​
Darina [25.2K]

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A- 462.86

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8 0
3 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

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Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

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3 years ago
Can u help me i dont het it please help me thanks
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It’s 60.1 do 956.4/15.9
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