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yuradex [85]
3 years ago
9

Graph x+y=8 and x-y=4

Mathematics
1 answer:
yanalaym [24]3 years ago
8 0

Answer:

See attached photo for graphs.  

Step-by-step explanation:

The first step is to solve each equation for y, then graph using slop-intecept form...

x + y = 8

 

  y = -x + 8         (subtract x from both sides)

x - y = 4

   -y = -x + 4     (subtract x from both sides)

       y = x - 4       (divide both sides by -1)    

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Please help! I'll give 50 points!!
bonufazy [111]

Pythagoras' theorem, is a basic relationship between the three sides of a right triangle in Euclidean geometry. The length of side c is 4√2 units.

<h3>What is Pythagoras theorem?</h3>

The Pythagorean theorem, sometimes known as Pythagoras' theorem, is a basic relationship between the three sides of a right triangle in Euclidean geometry. The size of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides, according to this rule.

Given the length of a is 4 units, while the length of b is 4 units. Therefore, the length of side C is,

c = √(4²+4²) = √[2(4)²] = 4√2 units

Hence, the length of side c is 4√2 units.

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2 years ago
Solve 3 ^ (x - 8) = 8 for x using the change of base formula logb y = (log y)/(log b)
Vilka [71]

Answer:

x=3\log_3 (2) +8

Step-by-step explanation:

Here we are using power rule first.

Power rule = The logarithm of an exponential number is the exponent times the logarithm of the base [log(a)^{b}=b\times log(a)].

For the function given.

3^{(x-8)} = 8,using log function both sides.

(x-8)log(3)=log(8)

Now,

(x-8)=\frac{log(8)}{log(3)}

Adding 8 both sides.

x=\frac{log(8)}{log(2)} +8

And we know that 8=2^{3} so we can further write log(8)=log(2^{3})=3log(2)

Then we have x=\frac{3\log(2)}{\log 3} +8.

Now, using change of base formula:

\frac{\log y}{\log b}=\log_b y

So, \frac{\log 2}{\log 3}=\log_3 2

Our final answer is  x=3\log_3 (2) +8.

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Answer:

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algol13

Answer:

Step-by-step explanation:

(0,0)A baker doesn't use any cups of flour so he can't make any cookies

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