3 years ago

Will give Brainliest Summations with Algebraic Expressions Image Shown

1 answer:

7 0

$\displaystyle\\\sum_{n=3}^5(-2x-4n)=-2x-4\cdot3+(-2x)-4\cdot4+(-2x)-4\cdot5\\\sum_{n=3}^5(-2x-4n)=-6x-12-16-20\\\sum_{n=3}^5(-2x-4n)=-6x-48$

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Step-by-step explanation:

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