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iris [78.8K]
3 years ago
10

What is the solution set for the open sentence with the given replacement set?

Mathematics
1 answer:
White raven [17]3 years ago
7 0
The Answer is 2

I hope this helps
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Which of the following is not a characteristics of a plane?
xeze [42]
So b is the correct answer
5 0
3 years ago
If vector v has an initial point at P1 and a terminal point at P2, write v as multiples of the basis vectors That is, write v in
pantera1 [17]

Answer:

v=9i+3j

Step-by-step explanation:

The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).

The vector v is found by subtraction the initial point from the terminal point.

v=<4,1>-<-5,-2>

v=<4--5,1--2>

v=<9,3>

We write v as multiples of the basis vectors to obtain:

v=9i+3j

8 0
3 years ago
PLZ HELP!!!
Tpy6a [65]

Answer:

187.74\:\mathrm{cm}

Step-by-step explanation:

The area of a rectangle is given by l\cdot w. Therefore, we can set up the following inequality:

l\cdot 16 \leq 3,003.84.

Solving this inequality, we have:

l \leq 187.74.

Therefore, the largest length Carmen's painting can be is \fbox{$187.74\:\mathrm{cm}$}.

3 0
3 years ago
Divide the number 480 in a ratio of 3:5
Schach [20]

If it is a ratio of 3:5 you are dividing 480 into 8 parts (3+5).


So divide 480 by 8: 480/8 = 60


Then the ratio is (3x60):(5x60) or 180:300


To check it is correct, add up the two parts to see that they come to 480:


180+300 = 480. All good.


Hope this helps


6 0
3 years ago
Read 2 more answers
30+ Points!!!<br> 5. Solve the following inequalities.<br> a) 2 log3x – 2 logx3 -3 &lt;0
Ilya [14]

Answer:

I answered your last question also

2 log3x – 2 logx3 -3 <0

\mathrm{Subtract\:}2\log ^3\left(x\right)\mathrm{\:from\:both\:sides}

2\log ^3\left(x\right)-2logx^3-3-2\log ^3\left(x\right)

\mathrm{Simplify}

-2logx^3-3

\mathrm{Add\:}3\mathrm{\:to\:both\:sides}

-2logx^3-3+3

\mathrm{Simplify}

-2logx^3

Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)

\left(-2logx^3\right)\left(-1\right)>-2\log ^3\left(x\right)\left(-1\right)+3\left(-1\right)

\mathrm{Simplify}

2lx^3og>2\log ^3\left(x\right)-3

\mathrm{Divide\:both\:sides\:by\:}2lx^3o;\quad \:l>0

\frac{2lx^3og}{2lx^3o}>\frac{2\log ^3\left(x\right)}{2lx^3o}-\frac{3}{2lx^3o};\quad \:l>0\\

\mathrm{Simplify}

g>\frac{2\log ^3\left(x\right)-3}{2lx^3o};\quad \:l>0

Step-by-step explanation:

6 0
2 years ago
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