What is the solution set for the open sentence with the given replacement set?

Can someone please help me with math.

Nat2105 [25]

Answer:

I think -3

Step-by-step explanation:

3 0

3 years ago

The midpoint of AB is M(-1, -2)M(−1,−2). If the coordinates of AA are (1, 3)(1,3), what are the coordinates of BB?

Sholpan [36]

of the quotient of the rectangular prism of green green and green green yellow green eeewww

4 0

2 years ago

What is the slope of y = - x + 7

svet-max [94.6K]

$\green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}}$

What is the slope of y = - x + 7

$\red{ \bold{ \textit{STANDARD \: EQUATION}}}$

$y = mx + c$

$WHERE \\ m = SLOPE \\ c = Y - INTERCEPT$

$\huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}$

$\blue{A.T.Q}$

$y = mx + c \sim y = ( - 1)x + 7$

$\orange{SO}$

m= (-1)

which is equal to the slope of the equation .

$\red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star$

3 0

3 years ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

8 0

3 years ago

Read 2 more answers

Helia invested 4000 AED for 3 years with a compound interest rate of 1.5%, Calculate the worth of her investment at the end of t

sineoko [7]

Answer:

4180 AED

Step-by-step explanation:

Given data

Principal= 4000

Time= 3 years

Rate= 1.5%

The compound interest expression is given as

A= P(1+r)^t

substitute

A=4000(1+0.015)^3

A= 4000(1.015)^3

A= 4000*1.045

A= 4180

Hence the worth will be 4180 AED

6 0

3 years ago