A circle with radius of \green{2}2 start color green, 2, end color green sits inside a \blue{7 \times 11}7×11 start color blue,
7, times, 11, end color blue rectangle. what is the area of the shaded region
2 answers:
A circle with radius 2 sits inside a 7×11 rectangle. What is the area of the shaded region?
We draw the problem in the picture attached. The picture is not drawn to scale!
In order to find the shaded area, you need to subtract the area of the circle from the area of the rectangle.
Therefore:
A(rectangle) = b·h = 11×7
= 77 u²
A(circle) = π·r² = 3.14 · 2²
= 3.14 · 4
= 12.56 u²
A(shaded) = A(rectangle) - <span>A(circle)
= 77 - 12.56
= 64.44 u²
Hence, the shaded figure has an area of 64.44 square units.
</span>
We draw the problem in the picture attached. The picture is not drawn to scale!
In order to find the shaded area, you need to subtract the area of the circle from the area of the rectangle.
Therefore:
A(rectangle) = b·h = 11×7
= 77 u²
A(circle) = π·r² = 3.14 · 2²
= 3.14 · 4
= 12.56 u²
A(shaded) = A(rectangle) - <span>A(circle)
= 77 - 12.56
= 64.44 u²
Hence, the shaded figure has an area of 64.44 square units.
</span>
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Answer:
p = 10
Step-by-step explanation:
In order to solve an equation we must isolate the variable we're solving for, p.
We can do this by undoing operations in the equation.
First, multiply both sides of the equation by 14.
This gives you 4 + p = 14
Then, you can subtract 4 from both sides:
4 - 4 + p = 14 - 4
p = 10