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enyata [817]
3 years ago
8

A circle with radius of \green{2}2 start color green, 2, end color green sits inside a \blue{7 \times 11}7×11 start color blue,

7, times, 11, end color blue rectangle. what is the area of the shaded region

Mathematics
2 answers:
dimulka [17.4K]3 years ago
4 0

Answer:

78.1

Step-by-step explanation:

i got it wrong on khan academy so there you go.

shtirl [24]3 years ago
3 0
A circle with radius 2 sits inside a 7×11 rectangle. What is the area of the shaded region?

We draw the problem in the picture attached. The picture is not drawn to scale!

In order to find the shaded area, you need to subtract the area of the circle from the area of the rectangle.

Therefore:
A(rectangle) = b·h = 11×7 
                               = 77 u²

A(circle) = π·r² = 3.14 · 2²
                        = 3.14 · 4
                        = 12.56 u²

A(shaded) = A(rectangle) - <span>A(circle) 
                  = 77 - 12.56
                  = 64.44 u²

Hence, the shaded figure has an area of 64.44 square units.
             </span>
            

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The perimeter of a triangle is 170 feet and the sides are in the ratio of 25:14:12. Find the area of the triangle.
Viktor [21]
Let
x,y, and z the long sides of the triangle 

we know that

x+y+z=170 ft------> equation 1
x/y=25/14----> y=14x/25------> equation 2
y/z=14/12-----> equation 3
x/z=25/12----> z=12x/25------> equation 4

substitute equation 2 and equation 4 in equation 1
x+[14x/25]+[12x/25]=170------> multiply by 25 both sides
25x+14x+12x=4250
51x=4250
x=4250/51
x=250/3
y=14x/25------> y=(250/3)*(14/25)----> y=140/3
z=12y/14-----> (140/3)*12/14----> z=40

Using Heron's formula,
Area of the triangle = √s (s-a) (s-b) (s-c)
where s is the semiperimeter
s=170/2-----> s=85 ft
Area=√85*[85-250/3]*[85-140/3]*[85-40]
Area=9.22*[1.67]*[38.33]*[45]------> Area=26558.21 ft²

the answer is
26558.21 ft²
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Simplify (-8z+4) + (7z-7)
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Answer:

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