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valkas [14]
3 years ago
14

Help pleaseeee ASAP just tell me the answer

Mathematics
1 answer:
iragen [17]3 years ago
6 0

HEY MATE YOUR ANSWER IS HERE

★ GIVEN EQUATION ★

X + Y = 4

★ SOLUTION ★

LET VALUE OF X = 0 , 1 , 2 , 3 AND 4

WHEN X = 0

0 + Y = 4

Y = 4

WHEN X = 1

1 + Y = 4

Y = 3

WHEN X = 2

2 + Y = 4

Y = 2

WHEN X = 3

3 + Y = 4

Y = 1

WHEN X = 4

4 + Y = 4

Y = 0

NOW OUR 5 COORDINATES OF LINE X + Y = 4 ARE

A ( 0 , 4)

B ( 1 , 3 )

C ( 2 , 2)

D ( 3 , 1 )

E ( 4 , 0 )

THANKS FOR YOUR QUESTION HOPE THIS HELPS

can i have a brill

thank u

good luck

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A ball is launched upward from the ground with an initial velocity of 20 ft/s. The height of the ball at time t is represented b
Anastaziya [24]

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8 0
3 years ago
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Solnce55 [7]
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4 0
4 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

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By the Central Limit Theorem

Z = \frac{X - \mu}{s}

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Z = \frac{30054 - 30393}{472.81}

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0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

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