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Mnenie [13.5K]
3 years ago
5

Derivative of y=cos²x-sin²x

Mathematics
1 answer:
Leona [35]3 years ago
8 0
One thing to bear in mind with trigonometric expressions is that, the exponent location is next to the function name, instead of the whole expression, though it applies to the whole thing, namely cos²(x), is really [ cos(x) ]², and that matters for using the chain rule.

\bf y=cos^2(x)-sin^2(x)\implies y=[cos(x)]^2-[sin(x)]^2
\\\\\\
\cfrac{dy}{dx}=\stackrel{chain~rule}{2cos(x)\cdot -sin(x)}~~-~~\stackrel{chain~rule}{2sin(x)\cdot cos(x)}
\\\\\\
\cfrac{dy}{dx}=-2cos(x)sin(x)-2cos(x)sin(x)
\\\\\\
\cfrac{dy}{dx}=-4cos(x)sin(x)
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stiv31 [10]
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Step-by-step explanation:

The computation of the maximum allowable recurring debt is shown below:

Given ratio = 28:36

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Now the maximum alloweable recurring debt is

= $1,152 - $896

= $256
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