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xenn [34]
4 years ago
10

Finally, the switch on the electromagnet is reopened. The magnitude of the external magnetic flux through the wire loop ______ (

A. increases, B. decreases, C. remains constant), and there is _______ (A. zero, B. a clockwise, C. a counterclockwise) current induced in the loop (as seen from the left). Enter the letters corresponding to the responses that correctly complete the statement above. For example, if the correct answers are A and C, type
Physics
1 answer:
zubka84 [21]4 years ago
8 0

Answer:

Decreases ,,clockwise

Explanation:

         When  the switch is reopened then magnitude  of magnetic  flux through the   loop will decreases and  the direction of induced  current will  be clockwise  (when seen from clockwise.

So the  answer of the  fill in the  blank is decreases and  clockwise.

Answer - B  and B.

              B)  Decreases ,B)clockwise

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A car of mass 300kg starts from rest and travels upwards along a straight road of 450m inclined at an angle of 5 degree to the h
zhuklara [117]

Answer:

Look at the picture.

Explanation:

I solved all of questions except the length of the slope because I don't know about it.

3 0
3 years ago
Which kind of friction requires more force to overcome rolling or sliding fricton?
ANTONII [103]
Sliding friction is harder to overcome, and steals
more energy whenever you're moving.

That's why we switched from sleds to wheels
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8 0
3 years ago
Please help! Questions are in the picture
Mars2501 [29]

Answer:

3500j

0.250 kg

14.14 m/s

220500 j

93.91 m/s

Explanation:

K.E =1/2 m v^2

first question

1/2×700×10=3500 j

second question

2×78.2/25^2= 0.250 kg

Third question

8kj=8000j

root (2×8000/80)= 14.14 m/s

Last one

P.E=MGH

so it will be

P.E=50×450×9.8=220500 j

the speed

root (2×220500/50)=93.91 m/s

7 0
3 years ago
Given that the velocity of blood pumping through the aorta is about 30 cm/s, what is the total current of the blood passing thro
TiliK225 [7]

Answer:

94.248 g/sec

Explanation:

For solving the total current of the blood passing first we have to solve the cross sectional area which is given below:

A_1 = \pi R^2\\\\A_1 = \pi (1)^2\\\\A_1 = 3.1416 cm^2

And, the velocity of blood pumping is 30 cm^2

Now apply the following formula to solve the total current

Q = \rho A_1V_1\\\\Q = (1)(3.1416)(30)\\\\

Q =  94.248 g/sec

Basically we applied the above formula So, that the total current could come

3 0
4 years ago
A crate is pulled with a force of 165 N at an angle 30 ° northwest. What is the resultant horizontal force on the crate?
Ad libitum [116K]

Answer:

Resultant horizontal force = 143 N

Explanation:

Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;

Resultant horizontal force = 165 * cos 30

Resultant horizontal force = 142.89

Approximating to a whole number gives;

Resultant horizontal force = 143 N

5 0
2 years ago
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