A car of mass 300kg starts from rest and travels upwards along a straight road of 450m inclined at an angle of 5 degree to the h
orizontal and the speed of the car is 28m/s at the top of the slope. Determine its acceleration, the time taken to travel, the length of the slope, gain in kinetic energy and gain in gravitational potential energy
1 answer:
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Answer:
0.321659377 m/s²
1.383138458 m/s
0.321659377 m/s²
0.62667 m/s²
0.7044 m/s² and 27.17°
Explanation:
d = Diameter of rim = 13 in =
r = Radius =
= Final angular velocity =
= Initial angular velocity = 0
= Angular acceleration
t = Time taken = 4.3 s
Equation of rotational motion
Tangential acceleration is given by
The tangential acceleration of the bug is 0.321659377 m/s²
Tangential velocity is given by
The tangential velocity of the bug is 1.383138458 m/s
The tangential acceleration is constant which is 0.321659377 m/s²
Centripetal acceleration is given by
The centripetal acceleration of the bug is 0.62667 m/s²
The resultant of the acceleration gives us total acceleration
Direction is given by
The magnitude and direction of the acceleration is 0.7044 m/s² and 27.17°
Answer: Torque= tangential force × radius of the pulley
Explanation:
Pulley is a simple machine which helps us to lift loads by applying the force in a convenient direction. It consists of a grooved wheel which is free to rotate about an axle passing through the center of the pulley.
For a pulley, the torque tangential force × radius of the pulley
Pulleys can be used in combination also to achieve a desired output.