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riadik2000 [5.3K]
4 years ago
14

When you are ice skating, to get started, you push your stake backwards on the ice and, as a result, begin to move forward. whic

h law of motion is being describe in this scenario.
Physics
1 answer:
Flauer [41]4 years ago
6 0

The law of motion that is being described in this scenario is Friction. Friction between the skate and the ice is what's moving the skater forward.

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An 100 kg object traveling at 50 m/s collides (perfectly inelastic) with a 50 kg object initially at rest.
qaws [65]

Answer:

Option C. 5,000 kg m/s

Explanation:

<u>Linear Momentum on a System of Particles </u>

Is defined as the sum of the momenta of each particles in a determined moment. The individual momentum is the product of the mass of the particle by its speed

P=mv

The question refers to an 100 kg object traveling at 50 m/s who collides with another object of 50 kg object initially at rest. We compute the moments of each object

m_1=(100\ kg)(50\ m/s)=5,000\ kg\ m/s

m_2=(50\ kg)(0\ m/s) = 0

The sum of the momenta of both objects prior to the collision is

P=5,000\ kg\ m/s+0\ kg\ m/s

\boxed{ P=5,000\ kg\ m/s}

7 0
3 years ago
Um móvel realiza movimento retilíneo uniformemente
Alona [7]
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8 0
3 years ago
Help me I do not understand
ololo11 [35]

Answer:

170N

Explanation:

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4 0
4 years ago
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Sveta_85 [38]
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3 years ago
Why does a heavier object fall faster
Salsk061 [2.6K]

Explanation:

In a vacuum (no air resistance), it doesn't.  All falling objects, regardless of mass, accelerate at the same rate.

However, when air resistance is taken into account, heavier objects indeed fall faster than lighter objects, provided they have the same shape and size.  For example, a lead ball falls faster than a styrofoam ball.

To understand why, first look at what factors affect air resistance:

D = ½ρv²CA

where ρ is air density,

v is velocity,

C is drag coefficient,

and A is cross sectional area.

As falling objects accelerate, they eventually reach a maximum velocity where air resistance equals weight.  This is called terminal velocity.

D = W

½ρv²CA = mg

v = √(2mg/(ρCA))

If we increase m while holding everything else constant, v increases.  So two objects with the same size and shape but different masses will have different terminal velocities, with the heavier object falling faster.

7 0
3 years ago
Read 2 more answers
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