Answer:
You could try finding a familiar peer to join the activity with your child. Or ask your child who their friends are at school, or what they look for in a friend at school.
Answer:
a. λ = 647.2 nm
b. I₀ 9.36 x 10⁻⁵
Explanation:
Given:
β = 56.0 rad , θ = 3.09 ° , γ = 0.170 mm = 0.170 x 10⁻³ m
a.
The wavelength of the radiation can be find using
β = 2 π / γ * sin θ
λ = [ 2π * γ * sin θ ] / β
λ = [ 2π * 0.107 x 10⁻³m * sin (3.09°) ] / 56.0 rad
λ = 647.14 x 10⁻⁹ m ⇒ λ = 647.2 nm
b.
The intensity of the central maximum I₀
I = I₀ (4 / β² ) * sin ( β / 2)²
I = I₀ (4 / 56.0²) * [ sin (56.0 /2) ]²
I = I₀ 9.36 x 10⁻⁵
Automotive idustries made a paradigm shift in selection of viscometrics of engine lubricant,from higher to lower viscosity grade,for improving fuel economy
Explanation:
Answer:
The items here are describing either a condition in a later interacton or a protogalactic cloud. The results matching with spiral and elliptical galaxy are:
For spiral galaxy are options 6,3,2 and 5.
and for elliptical galaxy are options 4 and 1.
Explanation:
Here it is given that astrnomers suspect that types of galaxy can be affected both by the conditions which occurs due to protogalactic cloud and then from it forms the initial conditions and then by the later interactions with the other galaxies.
so, both types of galaxies are matched with their respective items given:
A. Spiral galaxy:
2. A galaxy collision results tostripping of gas.
3. The protogalactic cloud rotates in a very slow motion.
5. The density of protogalactic cloud is very high.
6. when the protogalactic cloud shrinks cloud forms very rapidly.
B. Elliptical galaxy:
1. The protogalactic cloud has high angular momentum.
4. Most of the protogalactic gases settles down into a disk.
