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SVEN [57.7K]
3 years ago
12

Pyramid math (algebra 1)

Physics
1 answer:
mixas84 [53]3 years ago
3 0
5436 7699 2360 3488 2113
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A sanding disk with rotational inertia 1.2 10-3 kg·m2 is attached to an electric drill whose motor delivers a torque of 10 N·m a
tensa zangetsu [6.8K]

Answer:

Angular momentum = 0.7 kg.m²/s

Angular velocity = 583.3 rad/s

Explanation:

1. The torque τ  is related to the angular momentum L by the relation

τ = ΔL/Δt

ΔL = τΔt

τ = 10 N. m

Δt = 70 ms = 70 × 10⁻³s

ΔL = (10 N. m) × (70 × 10⁻³s) = 700 × 10⁻³ kg.m²/s = 0.7 kg.m²/s

2. The rotational inertia I relates the angular momentum L to the angular velocity w

L = Iw

w = L/I

L =  0.7 kg.m²/s

I = 1.2 × 10⁻³ kg.m²

w = (0.7 kg.m²/s)/(1.2 × 10⁻³ kg.m²) = 583.3 rad/s

4 0
3 years ago
If a 40 kg gymnast and a 400 kg sumo wrestler each dropped from 1 m above the trampoline, find the final position of each athlet
Tomtit [17]
When you drop an object from some height on the spring objects initial potential energy is converted to kinetic energy, this kinetic energy is then used to compress the spring. Once all the energy is used the spring stops compressing and starts oscillating. 
We need to find how much the spring compressed in both cases.
From the above analysis, we can conclude that potential energy in the gravitational field has to be equal to the potential energy of compressed spring.
mgh=\frac{1}{2}kx^2
We solve for x (in our case h=1):
mg=\frac{1}{2}kx^2\\
x^2=\frac{2mg}{k}\\
x=\sqrt{\frac{2mg}{k}}
Now we just have to plug in the numbers:
$$Sumo\ wrestler(m=400kg):x=\sqrt{\frac{2mg}{k}}=0.81m\\

$$ Gymnast(m=40kg):x=\sqrt{\frac{2mg}{k}}=0.26m\\
8 0
3 years ago
A 0.350 kg block at -27.5°C is added to 0.217 kg of water at 25.0°C. They come to equilibrium at 16.4°C. What is the specific he
Gekata [30.6K]

The specific heat capacity of the block is 508J/kg^{\circ}C

Explanation:

As the block is placed into the water, heat energy is transferred from the water (which is at higher temperature) to the block (which is at lower temperature), until the block and the water are in thermal equilibrium (= same temperature).

Therefore, we can write:

Q_{water}=Q_{block}

Where

Q_{water}=m_w C_w (T_w-T_{eq}) is the heat energy released by the water, where

m_w = 0.217 kg is the mass of the water

C_w = 4186 J/kg^{\circ}C is the water heat specific capacity

T_w = 25.0^{\circ} is the initial temperature of the water

T_{eq}=16.4^{\circ} is the temperature at equilibrium

Substituting,

Q_{water}=(0.217)(4186)(25.0-16.4)=7812 J

Now we can write the heat energy absorbed by the block as

Q_{block}=m_b C_b(T_{eq}-T_b)

where

m_b=0.350 kg is the mass of the block

C_b is the specific heat capacity of the block

T_b = -27.5^{\circ} is the initial temperature of the block

And solving for C_b,

C_b=\frac{Q_{block}}{m_b(T_{eq}-T_b)}=\frac{7812}{(0.350)(16.4-(-27.5))}=508J/kg^{\circ}C

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

6 0
3 years ago
Scientists think that convection currents flow in earth’s
torisob [31]

Answer: convection currents does flow because God created the earth and God it makes life flow

Explanation:

God

7 0
3 years ago
A camcorder has a power rating of 10 watts. If the output voltage from its battery is 3 volts, what current does it use?
Gemiola [76]
The power is calculated using the following rule:
Power = voltage * current
We are given that:
power = 10 watts
voltage = 3 volts

Substitute with the givens in the above equation to get the value of the current as follows:
P = V*I
10 = 3*I
current (I) = 10/3 amperes
7 0
3 years ago
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