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SVEN [57.7K]
3 years ago
12

Pyramid math (algebra 1)

Physics
1 answer:
mixas84 [53]3 years ago
3 0
5436 7699 2360 3488 2113
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Un proyectil es lanzado horizontalmente desde una altura de 12 metro con una velocidad de 80 m/sg. a.Calcular el tiempo de vuelo
Naily [24]

Answer:

t= 1,56 s ,   x= 124,8 m , v = (80 i^ - 15,288 j ) m/s

Explanation:

Este es un ejercicio de lanzamiento proyectiles, comencemos por encontrar el tiempo que tarda en llegar al piso

        y = y₀ + v_{oy} t – ½ g t²

en este caso la altura inicial es y₀= 12 m y llega a y=0 , como es lanzado horizontalmente la velocidad vertical es cero (v_{oy}=0)

       0 = y₀ – ½ g t²

       t= √ (2 y₀/g)

calculemos

       t= √ ( 2 12 / 9,8)

       t= 1,56 s

El alcance del proyectil es la distancia horizontal recorrida  

        x = v₀ₓ t

        x = 80 1,56

        x= 124,8 m

La velocidad de impacto cuando toca el suelo

        vx = v₀ₓ = 80 ms

        v_{y} = v_{oy} – gt

        v_{y} = - 9,8 1,56

        v_{y} = - 15,288 m/s

la velocidad es

       v = (80 i^ - 15,288 j ) m/s

Traducttion  

This is a projectile launching exercise, let's start by finding the time it takes to reach the ground

        y = y₀ + v_{oy} t - ½ g t²

in this case the initial height is i = 12 m and it reaches y = 0, as it is thrown horizontally the vertical speed is zero (v_{oy} = 0)

       0 =y₀I - ½ g t²

       t = √ (2y₀ / g)

let's calculate

       t = √ (2 12 / 9.8)

       t = 1.56 s

Projectile range is the horizontal distance traveled

        x = v₀ₓ t

        x = 80 1.56

        x = 124.8 m

Impact speed when it hits the ground

        vₓ = v₀ₓ = 80 ms

        v_{y} = v_{oy} - gt

        v_{y} = - 9.8 1.56

        v_{y} = - 15,288 m / s

the speed is

       v = (80 i ^ - 15,288 j) m / s

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3 years ago
What is te leading cause of type 2 diabetes
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2 years ago
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An astronaut throws a wrench in interstellar space. How much force is required to keep the wrench moving continuously with const
andreev551 [17]

Answer:

0 N

Explanation:

This is a trick question, the mass of the wrench would be 0 due to it being in space and has no gravitational pull to weight it down. And since acceleration is defined as the rate and change of velocity with no respect of time and the wrench is moving at a constant velocity, that means the velocity is 0. and since F = m*a it would be F = 0 * 0 = 0 N

5 0
2 years ago
An alternator consists of a coil of area A with N turns that rotates in a uniform field B around a diameter perpendicular to the
svet-max [94.6K]

Answer:

(a): emf = \rm 2\pi f NBA\sin(2\pi ft).

(b): Amplitude of alternating voltage = 20.942 Volts.

Explanation:

<u>Given:</u>

  • Area of the coil = A.
  • Number of turns of coil = N.
  • Magnetic field = B
  • Rotation frequency = f.

(a):

The magnetic flux through the coil is given by

\phi = \vec B \cdot \vec A=BA\cos\theta

where,

\vec A = area vector of the coil directed along the normal to the plane of the coil.

\theta = angle between \vec B and \vec A.

Assuming, the direction of magnetic field is along the normal to the plane of the coil initially.

At any time t, the angle which magnetic field makes with the normal to the plane of the coil is 2\pi ft

Therefore, the magnetic flux linked with the coil at any time t is given by

\phi(t) = NBA\cos(2\pi ft)

According to Faraday's law of electromagnetic induction, the emf induced in the coil is given by

e=-\dfrac{d\phi}{dt}\\=-\dfrac{d(NBA\cos(2\pi ft))}{dt}\\=-NBA(-2\pi f\sin(2\pi ft))\\=2\pi f NBA\sin(2\pi ft).

(b):

The amplitude of the alternating voltage is the maximum value of the emf and emf is maximum when \sin(2\pi ft)=1.

Therefore, the amplitude of the alternating voltage is given by

e_o = 2\pi ft NBA.

We have,

N=100\\A=10^{-2}\ m^2\\B=0.1\ T\\f=2000\ rev/ min = 2000\times \dfrac{1}{60}\ rev/sec=33.33\ rev/sec.

Putting all these values,

e_o = 2\pi \times 33.33\times 100\times 0.1\times 10^{-2}=20.942\ Volts.

7 0
3 years ago
A springboard diver intending to do a somersault brings her knees and arms closer to her body during the dive. What effect does
Hoochie [10]

During the diving when a diver jumps off from platform he brings her knees and arms closer to the body

This is because when diver is in air he don't have any torque about his center of mass which shows that angular momentum of his body will remain constant during his motion in air

Now we can say product of his moment of inertia and his angular speed will remain constant always

So here if we decrease the moment of inertia of the body during our motion then angular speed will increase so that product will remain constant

and this is what the diver use during his diving

so correct answer will be

<u><em>It decreases her moment of inertia.</em></u>

7 0
3 years ago
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