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4 years ago

10

Jose has a family of 4. Is it more reasonable for Jose to purchase 3 pounds of potatoes for his family’s meal tonight or 13 poun

ds of potatoes?

1 answer:

Angelina_Jolie [31]4 years ago

5 0

I think 13 pounds for extras and all not sure just my thought :)

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Can someone explain to me how to find this?

Aleonysh [2.5K]

I hope this helps you

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3 years ago

Solve the given initial-value problem. the de is a bernoulli equation. x2 dy dx − 2xy = 4y4, y(1) = 1 2

mario62 [17]

$x^2\dfrac{\mathrm dy}{\mathrm dx}-2xy=4y^4$
$x^2y^{-4}\dfrac{\mathrm dy}{\mathrm dx}-2xy^{-3}=4$

Substitute $z=y^{-3}$ , so that $\dfrac{\mathrm dz}{\mathrm dx}=-3y^{-4}\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE in terms of $z(x)$ is

$-\dfrac13x^2\dfrac{\mathrm dz}{\mathrm dx}-2xz=4$
$x^2\dfrac{\mathrm dz}{\mathrm dx}+6xz=-12$
$x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-12x^4$

$\dfrac{\mathrm d}{\mathrm dx}\left[x^6z\right]=-12x^4$
$\implies x^6z=-\dfrac{12}5x^5+C$
$\implies z=-\dfrac{12}{5x}+\dfrac C{x^6}$
$\implies\dfrac1{y^3}=-\dfrac{12}{5x}+\dfrac C{x^6}$

and you can attempt to solve for $y$ explicitly from here if you wish.
In any case, given that $y(1)=\dfrac12$ (presumably that's what you meant to write), we'd get

$\dfrac1{\left(\frac12\right)^3}=-\dfrac{12}{5\cdot1}+\dfrac C{1^6}$
$8=-\dfrac{12}5+C\implies C=\dfrac{52}5$

giving a particular solution of

$\dfrac1{y^3}=-\dfrac{12}{5x}+\dfrac{52}{5x^6}$

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3 years ago

The product of two number is 105. if one number is -3 what is the other number

Anna11 [10]

Answer: -35

Step-by-step explanation:

You can check it by multiplying -3 and -35 you should get 105

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3 years ago

Does the choice of the base affect the area of a parallelogram

hram777 [196]

Yes because the base is equal to top and doubles the distance which affects the inside area.

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3 years ago

Suppose that you have 7 cookies to distribute between 13 children.

Oduvanchick [21]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

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3 years ago

Read 2 more answers