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Whitepunk [10]
3 years ago
14

SOMEBODY HELP NO LINKS PLZ AND THANK YOU

Mathematics
1 answer:
nydimaria [60]3 years ago
4 0
F(x) is showing the exponential function 2^(7-x)
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Mr. Gosain?(1 Aana = 31.8 m²) b) A real estate agent bought two triangular Kittas' having a common side as shown in the figure f
Sonbull [250]

The information given regarding the computation of the profit or loss shows that there's a loss of RS 500,000.

<h3>How to calculate the profit?</h3>

From the information given, it was stated that the real estate agent bought two triangular Kittas' having a common side as shown in the figure from two people for Rs 2000,000 altogether.

It was further depicted that he sold the land in the shape of a quadrilateral at Rs 1,500,000. In their case, the sale is less than the cost and therefore, there's a loss.

The loss will be:

= 2,000,000 - 1,500,000

= 500,000

Therefore, the information given regarding the computation of the profit or loss shows that there's a loss of RS 500,000.

Learn more about profit on:

brainly.com/question/1078746

#SPJ1

4 0
2 years ago
I need the answer pls
AleksAgata [21]

the answer is 32.........

8 0
3 years ago
The gravitational attraction betweentwo bodies varies inversely as thesquare of the distance between them.If the force of attrac
Sliva [168]

The force for the case 1 is 64 pounds and the distance is 9 feet, it is:

\begin{gathered} \frac{k}{9^2}=64 \\ k=5184 \end{gathered}

Now, if the force is 36 pounds, let solve for the distance:

\begin{gathered} \frac{k}{r^2}=36 \\ \frac{5184}{r^2}=36 \\ r^2=144 \\ r=12 \end{gathered}

Hence the answer is 12 feet.

3 0
1 year ago
He will reach home before the sun will set. correct the following sentence<br>​
hjlf

Answer:

he will reach home before the sun set

6 0
3 years ago
Read 2 more answers
A constant force of 85 N accelerates towards a 10 kg box from a speed of 3.0 m/s to a speed of 7.0 m/s as it goes 14 m along a h
photoshop1234 [79]

Answer:

Step-by-step explanation:

Let us find the acceleration of box .  

v² = u² + 2as

Putting the values

7² = 3² + 2 a x 14

a = 1.43 m /s²

If coefficient of friction be μ

force of friction = μ mg

= μ x 10 x 9.8

= 98μ

Net force pushing the box

= 85 - 98μ

Applying newton's second law

85 - 98μ = 10 x 1.43

98μ = 85 - 14.3

μ = .72

5 0
3 years ago
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