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3 years ago

Which decimal number is equivalent to 6/25? A.0.6 B.0.12 C.0.06 D.0.24

Mathematics

1 answer:

blondinia [14]3 years ago

8 0

D if you take 6/25 = 24/100 then change to a decimal and get 0.24

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twelve less than four times some number n is at least three more than the number. What values are possible for n?

IRISSAK [1]

4n -12 >n
4n > n + 12
3n > 12
n > 4
So 5,6,7,8,9, and so on

3 0

3 years ago

Someone please help. Please explain how I should do it!

Ede4ka [16]

Answer:

Step-by-step explanation:

if m and n are irrational number then the product of mn sometimes rational and sometime irrational

ex: √5 *√2=√10 irrational

ex: √8*√2=√16=4 rational

b-y=|x|+3

explain why |x|+3≥|x+3|

absolute value of any number is always positive

x |x|+3 ≥ |x+3|

1 4 = 4 in this case equal

2 5 5

-2 5 ≥ 1 in this case |x|+3≥|x+3|

in case of negative value of x then |x|+3>|x+3|

7 0

3 years ago

Substitution and elimination

nlexa [21]

Whats The Question ????

3 0

3 years ago

Show with work please.

kolbaska11 [484]

Answer:

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

Step-by-step explanation:

The identity you will use is:

$\csc \left(x\right)=\frac{1}{\sin \left(x\right)}$

So,

$\csc \left(\theta-\frac{\pi }{2}\right)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{\sin \left(-\frac{\pi }{2}+\theta\right)}$

Now, using the difference of sin

Note: state that $\text{sin}(\alpha\pm \beta)=\text{sin}(\alpha) \text{cos}(\beta) \pm \text{cos}(\alpha) \text{sin}(\beta)$

$\csc \left(\theta-\frac{\pi }{2}\right)=\frac{1}{-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)}$

Solving the difference of sin:

$-\cos \left(\theta\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(\theta\right)$

$-\cos \left(\theta\right) \cdot 1+0\cdot \sin \left(\theta\right)$

$-\text{cos} \left(\theta\right)$

Then,

$\csc \left(\theta-\frac{\pi }{2}\right)=-\frac{1}{\cos \left(\theta\right)}$

Once

$\text{sec}(-\theta)=\text{sec}(\theta)$

And, $\text{sec}(\theta)=-0.73$

$-\frac{1}{\cos \left(\theta\right)}=-\text{sec}(\theta)$

$-\frac{1}{\cos \left(\theta\right)}=-(-0.73)$

$-\frac{1}{\cos \left(\theta\right)}=0.73$

Therefore,

$\csc \left(\theta-\frac{\pi }{2}\right)=0.73$

3 0

3 years ago

Can you solve 5a please greatly appreciated.

timurjin [86]

Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5

Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)

3 0

3 years ago