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Law Incorporation [45]
3 years ago
8

Here’s a graph of a linear function write the equation that describes that function

Mathematics
1 answer:
posledela3 years ago
8 0

Answer:

The answer is y = 4x - 1

Step-by-step explanation:

First find two points on the line.

I will be using (-1, -5) & (1, 3).

Using the formula for slope, substitute in the values and solve:

y2-y1/x2-x1(This is the formula)

3--5/1--1(When using this formula, if y1 or x1 are negative, make them positive.)

3+5/1+1 or 8/2; which simplifies into 4/1.

So, the slope is 4/1.

Now we use point-slope form:

y - y1 = m(x-x1)

1. Substitute in the values.

y--5 = 4/1(x--1)

2. Simplify and distribute.

y + 5 = 4/1x + 4

3. Subtract 5 from both sides.

y = 4/1x - 1

4. Simplify.

y = 4x - 1

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Find the sum of the first 10 terms 0.5,0.9,1.3,1.7,..
IRINA_888 [86]

Answer:

0.5, 0.9, 1.3, 1.7, 2.1, 2.5, 2.9, 3.3, 3.7, 4.1

Now you can add them all

which is equal to 23

Step-by-step explanation:

8 0
3 years ago
What is the differencence betwenn the volume
DanielleElmas [232]
Small box volume is
12*2*7 3/4=186cubic inches
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3 0
3 years ago
Which phrase describes an unknown or changeable quanity?
qaws [65]
I believe the answer could be a variable
7 0
3 years ago
The Astronomical Telescope shop plans to introduce a new model based on the following information: Rent and utilities per period
dimaraw [331]

Using the profit concept, it is found that the break-even point is of 61.6 units.

  • Profit is given by revenue subtracted by cost.
  • The break-even point is when the revenue is the same as the cost, which means that the profit is zero.

In this problem:

  • Variable cost per unit x of $217, fixed cost of $5,420, thus, the cost equation is given by:

C(x) = 217x + 5420

Selling price per unit of $305, thus, the revenue equation is given by:

R(x) = 305x

The break-even point is the <u>value of x</u> for which:

R(x) = C(x)

Then

305x = 217x + 5420

88x = 5420

x = \frac{5420}{88}

x = 61.6

The break-even point is of 61.6 units.

A similar problem is given at brainly.com/question/4001746

5 0
3 years ago
Divide 16x3 – 12x2 + 20x – 3 by 4x + 5.
nalin [4]

Answer:

4x^2 - 8x + 15 - \frac{78}{4x+5}

Step-by-step explanation:

<em>To solve polynomial long division problems like these, it's helpful to build a long division table. Getting used to building these can make problems like this much simpler to solve.</em>

Begin by looking at the first term of the cubic polynomial.

What would we have to multiply 4x + 5 by to get an expression containing 16x^3? The answer is 4x^2, since (4x + 5) \times 4x^2 = 16x^2 + 20x.

This is the first step of our long division, and we write out the start of our long division table like this:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,16x^3 + 20x^2\\

On the left is the divisor. On top is 4x^2. In the middle is the polynomial we are dividing, and on the bottom is the result of multiplying our divisor by

The next step is to subtract the bottom expression from the middle one, like so:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,0x^3 - 32x^2\\

We are left with -32x^2. The next thing to do is to add the next term of the polynomial we are dividing to the bottom line, like this:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\

Now we return to the beginning of the instructions, and repeat the process: namely, what would we have to multiply 4x + 5 by to get an expression containing -32x^2? The answer is -8x, and we fill out our long division table like so:

{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,4x^2 - \,\,\,\,8x\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 - 40x\\

Once again, we subtract the bottom expression from the one above it, and include the next term of the divisor, like so:

{ }\qquad{ }\qquad{ }\quad{ }4x^2 - \,\,\,\,8x \,+ 15\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underline{- 32x^2 - 40x}\\{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\,\,\,\,\,60x - 3\\

And repeat. What do we multiply 4x + 5 by to get an expression containing 60x? The answer is 15. Our completed long division table looks like this:{ }\qquad{ }\qquad{ }\quad{ }4x^2 - \,\,\,\,8x \,+15\\4x + 5\quad)\!\!\overline{\,\,\,16x^3 - 12x^2 + 20x - 3}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\underline{16x^3 + 20x^2}\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\, - 32x^2 + 20x\\{ }\qquad{ }\quad{ }\quad{ }\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\underline{- 32x^2 - 40x}\\{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\qquad{ }\,\,\,\,\,60x - 3\\{ }\qquad{ }\hspace{3cm}\,\,\underline{60x + 75}\\{ }\hspace{4.3cm}\,\,-78

Now, the expression at the top,

4x^2 - 8x + 20x + 15

is our quotient, and the last number, -78, is our remainder.

Hence we arrive at the solution of

\frac{16x^3-12x^2+20x-3}{4x+5} =4x^2 - 8x + 15 - \frac{78}{4x+5}.

6 0
3 years ago
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