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3 years ago

Hannah paid $3.20 for 16 ounces of potato chips. Hank paid $3.23 for 17 ounces of potato chips. Who paid less per ounces?

Mathematics

1 answer:

zzz [600]3 years ago

8 0

Answer:

Hank did. He only paid 3 more cents for 17 ounces so it must be Hank.

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How do you find DE, Round to nearest 10th

Sergeu [11.5K]

Answer: $DE\approx6.0$

Step-by-step explanation:

Observe in the figure given in the exercise that four right triangles are formed.

In this case you can use the following Trigonometric Identity to solve this exercise:

$cos\alpha=\frac{adjacent}{hypotenuse}$

From the figure you can identify that:

$\alpha =53\°\\\\hypotenuse=10\\\\adjacent=BE=DE$

Then, you can substitute values:

$cos(53\°)=\frac{DE}{10}$

The next step is to solve for DE in order to find its value. This is:

$10*cos(53\°)=DE\\\\DE=6.01$

Finally, rounding the result to the nearest tenth, you get that this is:

$DE\approx6.0$

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3 years ago

A company sells fruit smoothies in two sizes: 6 ounces and 20 ounces. You know that a 6-ounce bottle contains 96 milligrams of s

expeople1 [14]

Answer:

320 milligrams of sodium

Step-by-step explanation:

Create a proportion where x is the milligrams of sodium a 20 ounce bottle has:

$\frac{96}{6}$ = $\frac{x}{20}$

Cross multiply and solve for x

1920 = 6x

320 = x

So, a 20 ounce bottle will have 320 milligrams of sodium

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2 years ago

Using the picture below, which angle is alternate interior to angle 5?

oee [108]

Answer:

angle 4

Step-by-step explanation:

Angle 4 is the opposite of angle 5, if you flip the paper upside down, you'll see that it is the same

7 0

2 years ago

Read 2 more answers

To hang a 9-ft hammock from a tree, you first tie one end to the trunk of the tree. When the hammock is tied on one end, it make

Delicious77 [7]

Hi mom mom I will call you

8 0

2 years ago

Find the projection of u onto v<br> URGENT HELP

padilas [110]

Given:

Two vectors are:

$u=\left$

$v=\left$

To find:

The projection of u onto v.

Solution:

Magnitude of a vector $v=\left$ is:

$|v|=\sqrt{a^2+b^2}$

Dot product of two vector $v_1=\left$ and $v_2=\left$ is:

$v_1\cdot v_2=a_1a_2+b_1b_2$

Formula for projection of u onto v is:

$Proj_vu=\dfrac{u\cdot v}{|v|^2}v$

$Proj_vu=\dfrac{\left \cdot \left }{(\sqrt{2^2+17^2)^2}}\left$

$Proj_vu=\dfrac{0\cdot 2+6\cdot 17}{4+289}\left$

$Proj_vu=\dfrac{0+102}{293}\left$

On further simplification, we get

$Proj_vu=\dfrac{102}{293}\left$

$Proj_vu=\left$

Therefore, the projection of u onto v is $Proj_vu=\left$ .

3 0

3 years ago