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7nadin3 [17]
3 years ago
12

The measure of an exterior angle of a triangle is ______ the sum of the measures of the __________ remote interior angles.

Mathematics
1 answer:
stich3 [128]3 years ago
5 0

Answer:

It's option E.

Step-by-step explanation:

The measure of an exterior angle of a triangle EQUAL TO the sum of the measures of the TWO remote interior angles,

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Find a formula for the linear function with slope -9 and x-intercept 2.
gregori [183]
Hello : 
<span> formula for the linear function with slope -9 and x-intercept 2 is : 
y - 0 = -9(x-2)
y= -9x +18

</span>
4 0
3 years ago
A college has a 30% completion rate, meaning that 30% of all students who start at the college complete the goal they set. The p
RSB [31]

Answer:

45%

Step-by-step explanation:

For simplicity, let use assume there are 100 students in the school.

No. of students to complete college = (30/100) x 100 = 30 Students

President wants to increase by 50% = (50/100) x 30 = 15 Students

New set goal = 30 + 15 = 45 students.

Total number of students = 100 students

Therefore;

Rate goal % = (45/100) x 100% = 45%

4 0
3 years ago
3. A piece of white oak has a densityof 0.77 g/cm and a mass of 100 g,what would be the volume of thesample? PLEASE HELP!
Nezavi [6.7K]
\text{Volume}=129.87cm^3

Explanation

Step 1

the density of an object is given by:

\text{density}=\text{ }\frac{mass}{\text{volume}}

Step 2

let

\begin{gathered} \text{density}=0.77\frac{g}{cm^3} \\ \text{mass}=\text{ 100 g} \\  \end{gathered}

Step 3

replace,

\begin{gathered} \text{density}=\text{ }\frac{mass}{\text{volume}} \\ 0.77\frac{g}{cm^3}=\frac{100g}{\text{volume}} \\ \text{volume}\cdot0.77\frac{g}{cm^3}=\text{1}00\text{ g} \\  \\ \text{Volume}=\frac{100\text{ g}}{0.77\frac{g}{cm^3}} \\ \text{Volume}=129.87cm^3 \end{gathered}

I hope this helps you

5 0
1 year ago
A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On
anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

h(x)=ax(x-7)             ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

4=a(3)((3)-7)

4=a(3)(-4)

\dfrac{4}{(3)(-4)}=a

-\dfrac{1}{3}=a

Putting a=-\dfrac{1}{3}, we get

h(x)=-\dfrac{1}{3}x(x-7)              ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)

h(1.5)=-(0.5)(-5.5)

h(1.5)=2.75

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.

4 0
3 years ago
0.3% of what number is $0.66?
UNO [17]
$0.66 / 0.3% = 2.2
Check:
2.2 * 0.3 = 0.66

Hope this helps!
8 0
3 years ago
Read 2 more answers
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