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Sholpan [36]
3 years ago
13

A bag contains 6 red balls numbered 1, 2, 4, 5, 8, 9 and 4 white balls numbered 3, 6, 7, 10,

Mathematics
1 answer:
geniusboy [140]3 years ago
6 0

Answer:

60%

a. 80%

b. 70%

Step-by-step explanation:

In this case we are first asked for the probability that when drawing a ball at random it is 8, 9 and 4 white balls numbered 3, 6, 7, 10, that is 6 balls. We know that there are a total of 10 balls since they are 6 red and 4 white, 6 + 4 = 10.

Therefore the probability is:

6/10 = 0.6

that is to say that the probability that it is one of these balls is 60%

to. that is red or odd,

red are 1, 2, 4, 5, 8, 9 and in addition to that, in white there is one with 3 and with 7 that are odd, making them 8 balls, therefore:

8/10 = 0.8

In other words, the probability is 80%

b. white or even,

the white ones are 3, 6, 7, 10 and in the red ones the 2, 4 and 8 are even, that is to say that they are 7 balls, which means that:

the probability is:

7/10 = 0.7

The probability is 70%

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borishaifa [10]
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Solving for x:  </span><span>9/x-4/y=8       Mult all 3 terms by xy to eliminate the fractions.

9(xy)/x - 4xy/y = 8xy         =>       9y - 4x = 8xy, or 9y = 4x + 8xy = 4x(1+2y)

                                                                        then 9y = x [ 4(1+2y) ]
                                                                                     9y
                                                            therefore x = ------------
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Solve for y using a similar approach.

</span>
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