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Sedaia [141]
3 years ago
14

A supervisor must split 60 hours of overtime between five people. One employee must be assigned twice the number of hours as eac

h of the other four employees. How many hours of overtime will be assigned to each employee?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
6 0
<h3>4 people do 10 hours and one person does 20 hours</h3>

<em><u>Solution:</u></em>

Given that,

A supervisor must split 60 hours of overtime between five people

One employee must be assigned twice the number of hours as each of the other four employees

Let  "x" be the number of hours overtime per person.

One person does 2x hours of overtime

Which means,

(number of hours overtime per person)(6 person) = 60 hours

6x = 60

x = 10

Thus, 4 people do 10 hours and one person does 20 hours

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tatyana61 [14]
The weight of an object is the product of its mass and the acceleration of gravity.
If g[e] is the acceleration of gravity on earth, and g[M] the same for Mars and g[m] the same for the moon,
then m[M]=m[e]g[M]/g[e] and m[m]=m[e]g[m]/g[e] where m[ ] denotes mass. Note that weight=mg (measured in newtons) while mass is in kilograms.
If g[M]=g[e]/3 and g[m]=g[e]/6 approximately. Then the weight of an object on Mars will be about a third of what it is on earth, while on the moon it would be about a sixth of what it is on earth.
4 0
3 years ago
I need help with this 2 please
xeze [42]

Answer:

D

Step-by-step explanation:

The formula for C is

C=2πr (using 3.14 as pi)

so C=2(3.14)(45)

so C=90(3.14)

so C≈282.6 or D

7 0
3 years ago
A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin
Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

T_1cos\theta_1-T_2cos\theta_2=0           (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

T_1sin\theta_1+T_2sin\theta_2-W=0               (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2

Then, you sum the equations:

T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2        (3)

Next, you use the following identity:

sin^2\theta+cos^2\theta=1

and you obtain in the equation (3):

T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°

With this values you can calculate the value of the another angle, by using the equation (1):

\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0
3 years ago
The graph below represents the distance a pilot is from the home airport during a period of time. A graph titled Pilot's Distanc
Simora [160]

Answer:

the awswer would have to be 7

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the current density of the solution a/m2
Jlenok [28]

Current density of solution a/m2 is given below

Step-by-step explanation:

Current density is the measure of current generated per unit surface area of electrode.

Eg: In microbial fuel cell/fuel cells, if you are using electrode with size of 5cm x 2cm and current produced is 200mA, then current density will be,

CD= Current/(projected area of electrode)

area of rectangle= LxB= 5cm x 2cm =10cm2

CD= 200mA/10cm2

CD= 20mA/cm2

Your Current will be 200mA.

Current density will be 20mA/cm2.

8 0
3 years ago
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