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2 years ago

A square garden has a side length that is 3 meters shorter than the length

Mathematics

1 answer:

podryga [215]2 years ago

5 0

This isnt a question or a square . squares have equal sides

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Factorise 36x³y-225xy³

blagie [28]

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6 0

2 years ago

Read 2 more answers

Find the degree of the polynomial: a^3+3a^2−5a

emmainna [20.7K]

Answer:

The degree of the polynomial is 3

Step-by-step explanation:

Given:

$a^3+3a^2-5a$

To Find:

The degree of the polynomial= ?

Solution:

The degree of the polynomial is the value of the greatest exponent of any expression (except the constant ) in the polynomial. To find the degree all that you have to do is find the largest exponent in the polynomial

Here in the given polynomial

$a^3+3a^2- 5a$

The terms are

$a^3$

$3a^2$

$5a$

The term $a^3$ has the largest exponent of 3

Note: The degree of the polynomial does not depend on coefficients of the terms

3 0

2 years ago

A farm has a square fenced-in area with side length x where the farm gives children pony rides. Adjacent to one entire side of t

Vika [28.1K]

Answer:

1) x²+4x=2700

2) 50x50

Step-by-step explanation:

Pony area = x²

line-up area=4x

x²+4x=2700

x²+4x-2700=0

(x-50)(x+54)

So x= 50 or -54. Since it can’t be a negative number, it must be 50.

CHECK:

Square = 50x50 = 2500

Line up area = 50x4 = 200

2500+200=2700 YES

6 0

2 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$