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3 years ago

7

Problem Page Maya purchased a prepaid phone card for $30 . Long distance calls cost 18 cents a minute using this card. Maya used

her card only once to make a long distance call. If the remaining credit on her card is $26.94 , how many minutes did her call last?

1 answer:

Helen [10]3 years ago

8 0

Her call lasted 17minutes

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(X^1/8 y^1/4 z^1/2)^8

adell [148]

(x^1/8 y^1/4 z^1/2)^8
(8 √x 4 √y √z^8)
(8 √x 8 √y^2 8 √z^4)^8
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3 years ago

Find the third term of (x^2 + 2)^4.

attashe74 [19]

Answer:

Step-by-step explanation:

$in~the~expansion~of~(x+a)^n\\T_{r+1}=ncr x^{n-r}a^r\\r+1=3\\r=3-1=2\\n=4\\4c2=\frac{4 \times 3}{2 \times 1} =6\\T_{2}=4(x^2)^{4-2}(2)^2\\=16(x^2)^2\\=16x^4$

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3 years ago

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What is the domain and range of this equation? Y= -1/4|x|+2

Sidana [21]

The domain is (-∞,∞)
the range is (−∞,2]

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3 years ago

Find ST if S(-3, 10) and T(-2, 3)

FrozenT [24]

We have the following points and their coordinates:

$\begin{gathered} S(-3,10), \\ T(-2,3). \end{gathered}$

We must compute the distance ST between them.

The distance ST between the two points is given by:

$ST=\sqrt[]{(x_S-x_T)^2+(y_S-y_T)^2_{}},$

where (xS,yS) are the coordinates of the point S and (xT,yT) are the coordinates of the point T.

Replacing the coordinates of the points in the formula above, we find that:

$\begin{gathered} ST=\sqrt[]{(-3_{}-(-2)_{})^2+(10_{}-3_{})^2_{}}, \\ ST=\sqrt[]{1^2+7^2}, \\ ST=\sqrt[]{50}\text{.} \end{gathered}$

Answer: ST = √50

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1 year ago

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Reptile [31]

The simplest (and most commonly used) area calculations are for squares and rectangles. To find the areaof a rectangle multiply its height by its width. For a square you only need to find the length of one of the sides (as each side is the same length) and then multiply this by itself tofind the area.

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