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Elza [17]
3 years ago
7

The diameter of a circle has endpoints A(1, 3) and B(4, 7), what is the

Mathematics
1 answer:
lana [24]3 years ago
4 0

Answer:

The circumference of the circle is 5π

Step-by-step explanation:

First we need to calculate the diameter  

for this we have to know the distance between A(1, 3) and B(4, 7)

X =  Xb - Xa

X = 4 - 1

X = 3

Y = Yb - Ya

Y = 7 - 3

Y = 4

b - a = (3 , 4)

now that we have the distance of x and r we can calculate its distance using Pythagoras

h = hypotenuse

x = leg 1 = 3

y = leg 2 = 4

h² = x² + y²

we replace the known values

h² = (3)² + (4)²

h² = 9 + 16

h² = 25

h = √25

h = 5

The diameter of the circle is 5

Now we need to calculate the circumferencefor this we need to use the circumferenc formula of a circle:

c = circumference

d = diameter = 5

π = pi

c = π * d

we replace with the known values

c = 5  * π

c = 5π

The circumference of the circle is 5π

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What is the value of x?<br><br><br><br> Enter your answer in the box.
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0.6 per second

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3 years ago
Find two consecutive integers whose sum is 73. Which of the following equations could be used to solve the problem?
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Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic
Free_Kalibri [48]

The equation for the situation is y=200(\frac{2}{3})^{x}

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is y=a(b)^{x} , where

  • a is the initial value
  • b is the growth/decay factor
  • If b > 1, then it is a growth factor
  • If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is \frac{2}{3}

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is y=a(b)^{x} , where y represent the

   population in x years

∵ a = 200

∵ b = \frac{2}{3}

∴ y=200(\frac{2}{3})^{x}

The equation for the situation is y=200(\frac{2}{3})^{x}

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ 5=200(\frac{2}{3})^{x}

- Divide both sides by 200

∴ 0.025=(\frac{2}{3})^{x}

- Insert ㏒ for both sides

∴ log(0.025)=log(\frac{2}{3})^{x}

∴ log(0.025)=xlog(\frac{2}{3})

- Divide both sides by log(\frac{2}{3})

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation  in brainly.com/question/10666510

#LearnwithBrainly

8 0
3 years ago
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