Question

At the beginning of six grade Kevin was 4’10” tall. at the end of ninth-grade he was 5’9” tall. what was the percentage of increase in Kevin height?

Answer 1

Answer:

Kevin's height increased 19.05%

Step-by-step explanation:

Height of Kevin at the beginning of sixth grade = 4’10”

Height of Kevin at the end of ninth grade = 5’9”

What was the percentage of increase in Kevin height?

For answering this question, we should convert Kevin's heights to decimal number, this way:

1 feet = 12 inches

4’10” = 4 10/12 = 4.83

5’9” = 5 9/12 = 5.75

Now, let's use the Direct Rule of Three:

Height     Percentage

4.83              100

5.75                 x

***********************************

4.83x = 5.75 * 100

4.83x = 575

x = 575/4.83

x = 119.05

119.05 - 100 = 19.05

Kevin's height increased 19.05%