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Studentka2010 [4]
3 years ago
13

Jan's motorboat travels at a speed of 14 mph in still water. Booth river flows at a speed of 4 mph. How long will it take Jen to

travel 16 miles upstream? 16 miles downstream?
Mathematics
2 answers:
Leya [2.2K]3 years ago
8 0
Upstream: 14 - 4 = 10. Miles per hour.
16 miles = 1.6 hours.

Downstream: 14 + 4 = 18.
16 miles = 16/18 = 8/9 or 0.888 of an hour.

Musya8 [376]3 years ago
5 0
Upstream 1hr and 54 minutes and downstream about 57 minutes
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It has a slope of 1.

Step-by-step explanation:

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The two points I picked where

(-2,0) and (-1,1)

All you do is subtract the two points. Remember rise over run or y/x

1 -0 = 1

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What is the order of rotational symmetry for a rhombus?
Ulleksa [173]

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  2

Step-by-step explanation:

The order (or degree) of rotational symmetry of a rhombus is 2. This is because it looks the same only when rotated 0° or 180° (2 angles, total).

6 0
3 years ago
Read 2 more answers
The art teacher needs 70 markers for her classes. The markers come in packages of 15. How many packages of markers will the art
Temka [501]

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5

Step-by-step explanation:

Take the number of markers and divide by the number in each package

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4.6666repeating

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5 0
3 years ago
HELP ME QUICK: Suppose AB has one endpoint at A(0, 0). If (5, 3) is the midpoint of AB, what are the coordinates of point B?
DiKsa [7]

Answer:

<h3>           B(10, 6)</h3>

Step-by-step explanation:

If P is midpoint of AB and:  A(0,\,0)\,,\quad P(5,\,3)\,,\quad B(x_B,\,y_B)

then:

x_P-x_A=x_B - x_P\qquad\quad\ \wedge\qquad y_P-y_A=y_B - y_P\\\\ 5-0=x_B-5\qquad\quad\wedge\qquad 3-0=y_B -3\\\\ x_B=5+5\qquad\qquad\wedge\qquad\ \ y_B=3+3 \\\\ {}\quad x_B=10\qquad\qquad\wedge\qquad\qquad \ y_B=6

5 0
3 years ago
I need help with this question i dont understand it
RUDIKE [14]
The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2}  }
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
\sqrt{(3-2) ^{2}+(4-3) ^{2}  }
which simplifies to
\sqrt{(1 )^{2}+(1) ^{2}  } which is \sqrt{2}
So that is the length of both MN and LM.  So far our perimeter is \sqrt{2} + \sqrt{2}=2 \sqrt{2}
Now let's use the same formula to find out the length of one of the longer segments:
\sqrt{(5-3) ^{2} +(3-2) ^{2} }
which simplifies down to
\sqrt{(2) ^{2} +(1) ^{2} }
which is of course \sqrt{5}
Since we have 2 of those lengths, \sqrt{5} + \sqrt{5}=2 \sqrt{5}
So our perimeter is, in the end, 2 \sqrt{2}+2 \sqrt{5}
That's the third choice down
7 0
3 years ago
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