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3 years ago

Given the expression

Mathematics

1 answer:

storchak [24]3 years ago

7 0

the student is wrong because the Constant coefficient is 5 not 3.

constant coefficient is that which have no variable but in the opinion of the student the coefficient is 3 which have a variable x.

so the student is wrong.

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The surface area of this triangular pyramid, whose base and lateral faces are congruent equilateral triangles, is __ square inch

DedPeter [7]

Answer:

The surface area is equal to $390\ in^{2}$

Step-by-step explanation:

The surface area of the triangular pyramid is equal to the area of its four triangular faces

In this problem

$SA=4[\frac{1}{2}(b)(h)]$

we have

$b=15\ in$

$h=13\ in$

substitute the values

$SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}$

4 0

3 years ago

Read 2 more answers

Assume that Emily (who has CF, a recessive disease (aa)) decides to have children with a man who does not have CF and who has no

alukav5142 [94]

Answer:100%. Probability

Step-by-step explanation:

Emily = aa

Man = AA

After crossing the two, the result wI'll be Aa, Aa, Aa, Aa

Since every result has a carrier(a) in it, makes it 100% probability.

7 0

3 years ago

Need help will mark Brainliest

Svetach [21]

Answer:

250 ft.

Step-by-step explanation:

It seems that you are learning the side-splitter theorem right now. If a line is parallel to one side of the triangle and intersects the other two sides, it divides the side proportionally. From the picture we can tell that the streets are parallel, with a line of intersection. Therefore, we can create the following equation of proportionality:

$\frac{375}{300} = \frac{x}{200}$

Now that we have this equation, we can use the butterfly method to solve for x. We cross multiply:

$375*200=300x\\$

Now, all we have to do is isolate the variable to find x:

$75000=300x\\x=250$

Therefore, the distance of Orange Ave between the 3rd St. and 4th St. is 250 ft.

I hope this helps! Please let me know if you have any further questions :)

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2 years ago

Plz help !! Financial algebra

aleksklad [387]

Answer:

$8.85

Step-by-step explanation:

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2 years ago

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Find the second derivative, do not have to simplify

zlopas [31]

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$f'(x)=\left\{[\cos(\pi x)]^{-1}\right\}'=-[\cos(\pi x)]^{-2}\cdot[-\sin(\pi x)]\cdot\pi\\\\=\dfrac{\pi\sin(\pi x)}{[\cos(\pi x)]^2}=\pi\dfrac{\sin(\pi x)}{\cos(\pi x)}\cdot\dfrac{1}{\cos(\pi x)}\\\\=\pi\tan(\pi x)\sec(\pi x)$

6 0

2 years ago