X=9x y=-2 and the rest is filled in
A. PT and TQ are equal since they are both bisected by T. So, set them equal to each other you get the equation:
5x+3 =48
5x=45
x=9
Answer:
f is not defined at x = 3 ⇒ answer (b)
Step-by-step explanation:
∵ f(x) = x² - x - 6/x² - 9 is a rational function
∴ It will be undefined at the values of x of the denominator
∵ The denominator is x² - 9
∵ x² - 9 = 0 ⇒ x² = 9 ⇒ x = ±√9
∴ x = ± 3
∴ f(x) can not be defined at x = 3
∴ The f(x) can not be continuous at x = 3
∴ The answer is (b)
You solve an equation like this by adding the opposite of the constant to both sides of the equation.
... V -16 +16 = -32 +16 . . . . . addition property of equality: if a=c, then a+b = c+b
... V + 0 = -16 . . . . . . . . . . . . additive inverse property of integers: -16+16 = 0
... V = -16 . . . . . . . . . . . . . . . identity element of addition: V+0 = V
_____
<em>You can always do the same thing to both sides of an equation.</em> Here, it is useful to add the opposite of -16 to both sides. That way the constant on the left becomes zero, so you only have the variable by itself—which is what you want.
Answer:
Step-by-step explanation:
For p'(4):
For q'(8):
