Step-by-step explanation:
d(t) = -16t² + 96t + 112
A) The quarter's initial height is at t = 0.
d(0) = -16(0)² + 96(0) + 112
d(0) = 112
The quarter is tossed from a height of 112 feet.
B) The maximum height is at the vertex of the parabola, which is at x = -b/(2a).
t = -(96) / (2 × -16)
t = 3
The quarter reaches its maximum height after 3 seconds.
C) d(3) = -16(3)² + 96(3) + 112
d(3) = 256
The quarter reaches a maximum height of 256 feet.
D) When the quarter lands in the water, d(t) = 0.
0 = -16t² + 96t + 112
0 = t² − 6t − 7
0 = (t + 1) (t − 7)
t = -1 or 7
Since t can't be negative, t = 7. So the quarter lands in the water after 7 seconds.
The correct answer for the exercirse shown in the figure attached is the first option, which is: Calculate the area of the circle A and circle B and calculate the difference.
To calculate the area of the circle A and the circle B, you must apply the formula for calculate the area of a circle, which is shown below:
A=πr²
A is the area of the circle.
r is the radius of the circle.
To calculate the difference, you only have to substract the result of the area of the circle A and the area od the circle B:
At=Aa-Ab
The probability that all three are blue it's 3:14
Answer:
-14a -14- 27/a-2 hope this helps
Step-by-step explanation:
Step-by-step explanation:
Amount of water left = 250 - 9x.
