Answer:
AuCl
Explanation:
Given parameters:
Mass of Gold = 2.6444g
Mass of Chlorine = 0.476g
Unknown:
Empirical formula = ?
Solution:
Empirical formula is the simplest formula of a compound. Here is the way of determining this formula.
Elements Au Cl
Mass 2.6444 0.476
Molar mass 197 35.5
Number of moles 2.6444/197 0.476/35.5
0.013 0.013
Divide by the
smallest 0.013/0.013 0.013/0.013
1 1
The empirical formula of the compound is AuCl
Answer:
If you're looking at the data as a whole, it would most likely be 100ml.
Explanation: The definition of precise is data close together so 100ml is furthest away from the other recorded numbers
Answer:
A) At stage 1 it begins to transmit electrons
B) Electron #2 because it jumped from level 1 to level 4
Explanation:
Answer:
Density 0.97 g.cm -3 at 20 °C
Melting point 97.5 °C
Boiling point 883 °C
oxidation states +1, −1 (rare)
Explanation:
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