Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
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Hi!
So the original formula for a problem likes this or a quadratic is:
ax^2 + bx+ c
so a is the accelaration; b is the initial velocity; and c is the initial height
so none of those are the zeros, which means c is out
zeros are the x values when y is 0, that also means when the parabola crosses the x axis
so d is out too because the maximum height is the vertex which mean that there would probably be a y value. in some cases the vertex is the zero, but not here
B is out because x isn't time it is distance
your answer is A!
Hope this helps!
So first find the circumfernece of the earth which is 24,901 times 5280
use a calculator
24,901 times 5280=131,477,280ft
1 ft=12 inches so 131,477,280 times 12=157,727,360 in
so 157,727,360 divide by the legnth of the case=1,577,727,360/15.1=104,485,255.62914 cases to go around the earth once so
million=1000 thousand
billion=1000 million
billion=1,000,000,000
2.6 billion=2,600,000,000
so 2,600,000,000/104,458,255.62914=24.88 or rounded up <u>they would go around the earth close to </u><u>25</u><u> times</u>
AREA OF THE BASES
base=legnth times width so 15.1 times 8.3 =125.33 in^2
multiply 125.33 in^2 by 2,600,000,000 and get 325,858,000,000 in^2 or 3.25858 times 10^11=area of the bases
PERIMETER OF THE BASES
perimeter of the bases 2Legnth+2Width times 2.6 billion
2(15.1)+2(8.3)=46.8
46.8 times 2.6 billion=121,680,000,000 inches or 1.2168 times 10^11= perimeter of all the bases
VOLUME
24 1/2 liter bottles means 24 times 1/2=12 liters in each pack
2.6 billion times 12=<u>31,200,000,000</u> liters or 3.12 times 10^10
2/9 of H?... , um I think
Answer:
I III and IV
Step-by-step explanation:
It cant be All four since yeah but im really sure that what i put is the answer
