Second moment of area about an axis along any diameter in the plane of the cross section (i.e. x-x, y-y) is each equal to (1/4)pi r^4.
The second moment of area about the zz-axis (along the axis of the cylinder) is the sum of the two, namely (1/2)pi r^4.
The derivation is by integration of the following:
int int y^2 dA
over the area of the cross section, and can be found in any book on mechanics of materials.
I believe the answer is C) Infinitely many solutions. I'm not the greatest at these types of questions, so I apologize, I could be wrong.
Hopefully that helped! :)
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Answer:
L'(4, -3)
Step-by-step explanation:
The reflection over the horizontal line y=-1 effects the transformation ...
(x, y) ⇒ (x, -2-y)
So, the coordinates of L are transformed to ..
L(4, 1) ⇒ L'(4, -2-1) = L'(4, -3)
http://www.purplemath.com/modules/specfact.htm
