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kirill [66]
3 years ago
5

On wednesday the farmers at the lewis farm picked 6 barrels of tomatoes. thursday, the farmers picked 3/5 as many tomatoes as on

wednesday. how many barrels of tomatoes did the farmers pick on thursday?
Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0
Wednesday - 6 barrels
Thursday-3/5*6=18/5=3.6 barrels
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Compare 7/21 and 3/18 using > < or =
sattari [20]
7/21 is greater than 3/18
=42/126 is greater than 21/126
8 0
3 years ago
Katie's swim team is having an end-of-season pizza party. When the party started, there was 50 slices of pizza. Now there are 20
kotykmax [81]

Answer:

30alice of pizza they eat

5 0
3 years ago
Please help:
Fudgin [204]

Answer:

\angle 1 =47^o\\\angle 2 = 133^o\\\angle 4 = 133^o

Step-by-step explanation:

Notice that angles <1 and <3  are opposed by the vertex, which makes them of equal measure, therefore, <1 = 47 degrees.

Notice as well that angles <1 and <2 combine into a straight line, therefore, they are supplementary angles whose addition gives 180 degrees then we can find the value of angle <2 via:

\angle 1 + \angle 2 = 180^o\\47^o + \angle 2=180^o\\\angle 2 = 180^o-47^o\\\angle 2 =133^o

And finally, angle <4 is opposite through the vertex to angle <2, and therefore they must have the same measure. So, <4 = 133 degrees.

5 0
2 years ago
Please help .<br> From the equation, what is the value of the radius, r ? x2 + y2 = 144
ale4655 [162]

Answer:

should be 12 if the x and y are squared. If you meant 2x and 2y than 12 is incorrect.

Step-by-step explanation: 144=r^2.

3 0
3 years ago
Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
Aleksandr [31]

Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

x+y+z=9439

Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

\begin{gathered} z+136+z+117+z=9439 \\ 3z=9439-136-117 \\ 3z=9186 \\ z=\frac{9186}{3} \\ z=3062 \end{gathered}

Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
1 year ago
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