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lianna [129]
3 years ago
11

How many valence electrons are available for bonding in silicon

Chemistry
2 answers:
Ray Of Light [21]3 years ago
7 0

Answer:

4

Explanation:

nadya68 [22]3 years ago
3 0

Answer: four

Explanation:silicon is in 4A and it take four more to get to eight

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Urgent plzz help meeee thx I HAVE EXAMEEE
USPshnik [31]

Answer: 2Ag^{+}(aq)+CO_3^{2-}(aq)\rightarrow Ag_2CO_3(s)

Explanation:

Spectator ions are defined as the ions which does not get involved in a chemical equation or they are ions which are found on both the sides of the chemical reaction present in ionic form.

The given chemical equation is:

2AgF(aq)+Na_2CO_3(aq)\rightarrow Ag_2CO_3(s)+2NaF(aq)

The complete ionic equation is;  

2Ag^{+}(aq)+2F^-(aq)+2Na^+(aq)+CO_3^{2-}(aq)\rightarrow Ag_2CO_3(s)+2Na^+(aq)+2F^-(aq)

The ions which are present on both the sides of the equation are Na^+ and F^- and are not involved in net ionic equation.

Hence, the net ionic equation is :

2Ag^{+}(aq)+CO_3^{2-}(aq)\rightarrow Ag_2CO_3(s)

6 0
3 years ago
Compute the atomic density (the number of atoms per cm3 ... rather than the mass density g/cm3) for a perfect crystal of silicon
serious [3.7K]

Answer:

        \large\boxed{\large\boxed{5.00\times 10^{22}atoms/cm^3}}

Explanation:

You can convert the <em>density</em> into <em>atomic density</em> using the <em>atomic weight </em>and Avogadro's number

A dimensional analysis is very helpful:

           \dfrac{g}{cm^3}\times \dfrac{mol}{g}\times \dfrac{atoms}{mol}=\dfrac{atoms}{cm^3}

Follow the chain: g cancels with g, mol cancels with mol; at the end, what remains is atoms/cm³, which is what you want.

Use that with your data:

         \dfrac{2.33g}{cm^3}\times \dfrac{1mol}{28.09g}\times \dfrac{6.022\times 10^{23}atoms}{mol}=\approx 5.00\times10^{22}atoms/cm^3

3 0
3 years ago
If the gas inside the flask is cooled so that its pressure is reduced from 797.3 torr to a value of 715.7 torr what will be the
nadezda [96]
The differential pressure is
797.9 - 715.7 = 82.2 torr = 138815.25 Pa
The height of the mercury in the open-end arm is calculated using
ΔP = ρgh
The density of mercury is 13560 kg/m3
The height of the mercury is
138815.25 Pa = 13560 kg/m3 (9.81 m/s2) h
h = 1.04 m
4 0
3 years ago
Name of Metallic compound VSe
Komok [63]

Answer: vanadium selenide

Explanation:

5 0
3 years ago
Read 2 more answers
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yuradex [85]
Halogens. Ex. fluorine can be the gas,bromine can be the liquid, and iodine could a solid all under room conditions.
4 0
4 years ago
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