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zimovet [89]
3 years ago
6

Sally and Juan’s science teacher has challenged her students to build a paper airplane that would stay airborne for ninety secon

ds. The students have two days to design and test their planes. The assignment will end with a "fly-off."
The teacher has given the students the problem. What is the next step in the technological design process?
A) building a model airplane
B) testing the model airplane
C) designing the model airplane
D) doing research on airplane design
Chemistry
1 answer:
denpristay [2]3 years ago
6 0
You would first do research.  (d)

The research part will help you find what ideas worked and what ideas didn't work.
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2 years ago
When 85 L of gas at 1.376 atm has its pressure changed to 0.154 atm, what is the new volume?
igor_vitrenko [27]

Answer:

<h2>759.48 L</h2>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{85 \times 1.376}{0.154}  =  \frac{116.96}{0.154}  \\  = 759.480519...

We have the final answer as

<h3>759.48 L</h3>

Hope this helps you

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If you were to use Lewis theory to predict the formula for the compound between rubidium and fluorine, it would most likely be:
goldenfox [79]

<u>Answer:</u> The formula of the compound formed between rubidium and fluorine is RbF

<u>Explanation:</u>

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Rubidium is the 37th element of the periodic table having electronic configuration of 1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1

This will loose 1 electron to form Rb^+ ion

Fluoride is the 9th element of the periodic table having electronic configuration of 1s^22s^22p^5

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To form RbF compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion

The formation of the given compounds is shown in the image below.

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