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3 years ago

Find three consecutive odd integers such that the first is 33 less than twice the second

Mathematics

1 answer:

wlad13 [49]3 years ago

6 0

the smallest integer will be x

2nd smallest will be x+2

largest will be x+4

therefore

2x+2-33=x

2x+2=x+33

2x=x+33-2

2x-x=33-2

x=31

the numbers will be 31,33 and 35

lets check whether it is correct

2x+2-33=x

31*2+2-33=31

62+2-33=31

64-33=31

31=31

therefore the answer 31,33 and 35 is correct

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Given:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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