Answer:
Remember that for a square of height H and length L, the area will be:
A = H*L
In this case, we know that the height is H = 4 units.
And the area is up to 48 square units
This means that the maximum possible area of this rectangle is 48 square units.
Then we have:
A ≤ 48 square units.
And we also could add:
0 square units < A ≤ 48 square units.
Now we can replace A by H*L = L*(4units)
0 square units < L*(4 units) ≤ 48 square units.
Now we need to divide all 3 sides by 4 units.
(0 square units)/(4 units) < L ≤ (48 square units)/(4 units)
0 units < L ≤ 12 units.
This is the range of lengths that Saritha can use to reconstruct the rectangle.
Now if we define b as the length of the bases, then we will use:
b = height = 4units.
Then:
1b = 4units.
(1 b/4units) = 1
This means that:
12 units = (12 units)*1 = (12 units)*(1 b/4units) = (12/4) b = 3 b
Then the range of possible values of L is:
0b < L ≤ 3b
Answer:
(x - 3)(x - 1)
Step-by-step explanation:
Consider the factors of the constant term (+ 3) which sum to give the coefficient of the x- term.
The factors are - 3 and - 1, since
- 3 × - 1 = + 3 and - 3 - 1 = - 4, hence
x² - 4x + 3 = (x - 3)(x - 1) ← in factored form
Answer:
230-240
Step-by-step explanation:
Answer:
x = 30° and 330°
Step-by-step explanation:
Assuming the intervals is {0 , 2π} or {0° , 360°}
So it means it lies in the 2nd and 4th quadrant because tangent is negative in the 2nd and 4th quadrant
so the two solutions are
x = 30° and 330° or
