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Verdich [7]
4 years ago
14

The club's total number of members will grow exponentially each month. She uses the given expression to model the number of club

members, in hundreds, after advertising for t months.
1.8(1.02)^12t

What does the value 1.8 represent?
Mathematics
1 answer:
mihalych1998 [28]4 years ago
6 0

Answer:

1.8 represents the initial number of the club members in hundreds.

Step-by-step explanation:

* Lets revise the exponential grows

- If a quantity grows by a fixed percent at regular intervals,

 the pattern can be depicted by this function.

- The function of the exponential growth is:

  y = a(1 + r)^x

# a = initial value (the amount before measuring growth)

# r = growth rate (most often represented as a percentage and

  expressed as a decimal)

# x = number of time intervals that have passed

* Now Lets study the problem to solve it

- The club's total number of members will grow exponentially

  each month

- The expression to model the number of club members, in

  hundreds, after advertising for t months is

  1.8(1.02)^12t

* Lets compare between this model and the function above

# a = 1.8 ⇒ initial number of members in hundreds

# r = 1.02 - 1 = 0.02 ⇒ growth rate

# x = 12t ⇒ number of time intervals

* 1.8 represents the initial number of the club members in hundreds.

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What number reduced by 14 percent equals 3440?
Wewaii [24]

Answer:

4000

Step-by-step explanation:

100 - 14 = 86

Here we shall take 86 to obtain the number easily

X × 86/100 = 3440

X = 3440 × 100 / 86

So X = 40 × 100

X = 4000

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3 years ago
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Question 1 (1 point)
kykrilka [37]

Answer:

The description for the problem is listed throughout the section below on explanations.

Step-by-step explanation:

The given values are:

The amount of bank loan = $22,000

Interest rate = 7.99%

Pays monthly = $700

So, the principal amount decreases by 700 per month.

Now,

The principal amount at the end of the m^{th} month = (22000 - 700 m)

Then,

The interest paid at the end of 1 year:

⇒ (22000)0.0799+(22000-700)0.0799+...+(22000-700(11))0.0799

On simplifying the above equation, we get

⇒ 0.0799[12(22000)-\frac{11\times 12}{2}\times 700]

⇒ 0.0799[264000-11\times 6\times 700]

⇒ 0.0799[264000-46200]

⇒ $17402.22

Therefore interest could be measured correctly at the end of each year, likewise.

⇒ (2200-700m)R+(22000-700(m+1))R+...+(22000-700(m+11))R

⇒ R[12\times 22000-700[12m+\frac{11\times 12}{2}]]

⇒ R[264000-700[12m+\frac{11\times 12}{2}]]

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7 0
4 years ago
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Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

(y+4)(3y−5)=0

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3y2+7y−20=0

Step 2: Factor left side of equation.

(3y−5)(y+4)=0

Step 3: Set factors equal to 0.

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6 0
3 years ago
What number is 1,000,000 greater than 337,676
mixas84 [53]
<span>Find the number that is 1 000 000 greater than 337 676.
This question is pretty simple because it is asking for a number that is 1 million greater or higher than 337 676
Simply add 337 676 to 1 000 000
=> 1 000 000 + 337 676
=> 1 337 676
Thus, the number that is 1 000 000 greater than 337 676 is 1 337 676.
To check the answer, do it backward:
=> 1 337 676 – 1 000 000
=> 337 676</span><span>

</span>



5 0
3 years ago
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