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I am Lyosha [343]
3 years ago
6

Graph the circle x2 + y2 - 12x + 6y +36 =0​

Mathematics
2 answers:
RoseWind [281]3 years ago
7 0

x^2+y^2-12x+6y+36=0

Top Point: (6,0)

Left Point: (3,-3)

Right Point: (9,-3)

Bottom Point: (6,-6)

Tresset [83]3 years ago
4 0

Answer:

x^2 +y^2 -12x +6y +36 =0

And we can complete the squares like this:

(x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2

And we got:

(x-6)^2 + (y+3)^2 = 9

And we have a circle with radius r =3 and the vertex would be;

V= (6,-3)

The graph is on the figure attached.

Step-by-step explanation:

For this case we have the following expression:

x^2 +y^2 -12x +6y +36 =0

And we can complete the squares like this:

(x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2

And we got:

(x-6)^2 + (y+3)^2 = 9

And we have a circle with radius r =3 and the vertex would be;

V= (6,-3)

The graph is on the figure attached.

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