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coldgirl [10]
4 years ago
8

Harita must memorize 90 measures of music for her cello solo at a concert. She plans on memorizing 18 new measures for every 3 d

ays of practice. Which equation can be used to determine m, the number of measures Harita still needs to memorize, as a function of d, the number of days of practice since she began learning the piece? m = 72 – 15d m = 90 – 6d m = 101 – 21d m = 108 – 3d
Mathematics
2 answers:
Ulleksa [173]4 years ago
8 0

Answer: m = 90 - 6d

Step-by-step explanation:

Just did the test

Black_prince [1.1K]4 years ago
3 0

Answer:

your answer your seeking for is m= 90-6d

Step-by-step explanation:

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D = b^2 -4ac solve for a 2/3 (x-18y) = 6y solve for x
seropon [69]

Answer:

a = \frac{b^2-d}{4c}

x = 27y

Step-by-step explanation:

Order of Operations: BPEMDAS

<u>Question 1</u>

Step 1: Write out discriminant

d = b² - 4ac

Step 2: Subtract b² on both sides

d - b² = -4ac

Step 3: Divide both sides by -1

b² - d = 4ac

Step 4: Divide both sides by 4c

a = \frac{b^2-d}{4c}

<u>Question 2</u>

Step 1: Write out equation

2/3(x - 18y) = 6y

Step 2: Distribute parenthesis

2/3x - 12y = 6y

Step 3: Isolate <em>x </em>by adding 12y on both sides

2/3x = 18y

Step 4: Divide both sides by 2/3

x = 27y

7 0
3 years ago
Which expression is equivalent to y x 48?
Nostrana [21]

Answer: (y*40)+(y*8)

Step-by-step explanation:

7 0
3 years ago
BRAINLYEST FOR FIRST PERSON AND 5 STARS!!!!!!!!!!! simplify 3 x 5/6=
ale4655 [162]

Answer:

1st= 2 1/2

2nd= ???

3rd= 1/3

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5th= 5/144

Step-by-step explanation:

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−125%+20/28=<br> help plzz
wlad13 [49]
-125%+20/28
-125/100+20/28
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The curve y = |x|/(sqrt(5- x^2)) is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point
iren [92.7K]
Absolute value
at x=2, the absolute value thing is positive
do this one
y=x \sqrt{5-x^2}
the derivitive is
\frac{dy}{dx}=\sqrt{5-x^2}- \frac{x^2}{ \sqrt{5-x^2} }
so the slope at x=2 is
\frac{dy}{dx}=\sqrt{5-2^2}- \frac{2^2}{ \sqrt{5-2^2} }=-3

a point is (2,2)
point slope form
y-y1=m(x-x1)
y-2=-3(x-2)
or
y=-3x+8
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3 0
3 years ago
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