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Svetach [21]
3 years ago
15

Could someone please help me solve this?

Mathematics
1 answer:
ryzh [129]3 years ago
6 0

Answer:

40

Step-by-step explanation:

(2/5)*n - 6 = 10                         Add 6 to both sides

(2/5)*n - 6 + 6 = 10 + 6             Combine

(2/5)*n = 16                               Multiply both sides by 5/2

(5/2)(2/5)n = 16*(5/2)

n = 80 / 2

n = 40  

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F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
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Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

3 0
3 years ago
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A 12-foot long ladder is leaning against a wall. It make sure an angle of 40 degrees with the ground. write an equation that can
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Answer:

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3 years ago
Circle experts...help! will give brainly to most detailed answer
azamat
<h3>Answer:  161 degrees</h3>

=========================================================

Explanation:

Line AE is a tangent while line AU is a secant. The angle formed by the secant and tangent lines connects with the arcs through this formula

secant tangent angle = (larger arc - smaller arc)/2

More specifically, we can say:

angle EAI = (arc EU - arc IE)/2

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x = 360-199

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The measure of minor arc IU is 161 degrees

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