Answer:
2 vertical asymptotes occurring at x = 5 and x = -1
Step-by-step explanation:
given
recall that asymptotic occur at the locations that will make the equation undefined. In this case, the asymptote will occur at x-locations which will cause the denominator to become zero (and hence undefined)
Equating the denominator to zero,
(x-5)(x+1) = 0
(x-5) =0
x = 5 (first asymptote)
or (x+1) = 0
x = -1 (2nd asymptote)
Answer:
The answer to your question is
sin Ф = 0.731 and sinФ = -0.731; cos Ф 0.682 and cos Ф = -0.682
Step-by-step explanation:
tan Ф = 1.072, 0 < Ф < 2 π, tan Ф is positive, find the solution in the first and third quadrangle.
- tan Ф = opposite side / adjacent side
- 1.072 / 1 = opposite side / adjacent side
- opposite side = 1.072 and adjacent side = 1
Calculate hypotenuse
c² = a² + b²
c² = 1.072² + 1²
c² = 2.149
hypotenuse = c = 1.466
First quadrangle
sin Ф = 1.072 / 1.466 = 0.731
cos Ф = 1 / 1.466 = 0.682
Third quadrangle
sin Ф = -1.072 / 1.466 = -0.731
cos Ф = -1 / 1.466 = -0.682
After 1 sec it would be 65 m/s
after 2 sec it would be 55 m/s
after 3 sec it would be 40 m/s
after 4 sec it would be 20 m/s
and so on. The equation for this is
S = 70 - (-5(t)) where s=speed and t=time passed
Answer:
<h2>6</h2>
Step-by-step explanation:
