a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

Then by linearity, we have


We know that : (a - b)(a + b) = a² - b²

We know that : 1 - sin²x = cos²x



We know that : sec²x = 1 + tan²x







Answer:
cool
Step-by-step explanation:
There isn't a picture to help you with.